This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.
%I A005563 M2720 #532 Aug 13 2025 21:23:43
%S A005563 0,3,8,15,24,35,48,63,80,99,120,143,168,195,224,255,288,323,360,399,
%T A005563 440,483,528,575,624,675,728,783,840,899,960,1023,1088,1155,1224,1295,
%U A005563 1368,1443,1520,1599,1680,1763,1848,1935,2024,2115,2208,2303,2400,2499,2600
%N A005563 a(n) = n*(n+2) = (n+1)^2 - 1.
%C A005563 Erdős conjectured that n^2 - 1 = k! has a solution if and only if n is 5, 11 or 71 (when k is 4, 5 or 7).
%C A005563 Second-order linear recurrences y(m) = 2y(m-1) + a(n)*y(m-2), y(0) = y(1) = 1, have closed form solutions involving only powers of integers. - _Len Smiley_, Dec 08 2001
%C A005563 Number of edges in the join of two cycle graphs, both of order n, C_n * C_n. - _Roberto E. Martinez II_, Jan 07 2002
%C A005563 Let k be a positive integer, M_n be the n X n matrix m_(i,j) = k^abs(i-j) then det(M_n) = (-1)^(n-1)*a(k-1)^(n-1). - _Benoit Cloitre_, May 28 2002
%C A005563 Also numbers k such that 4*k + 4 is a square. - _Cino Hilliard_, Dec 18 2003
%C A005563 For each term k, the function sqrt(x^2 + 1), starting with 1, produces an integer after k iterations. - _Gerald McGarvey_, Aug 19 2004
%C A005563 a(n) mod 3 = 0 if and only if n mod 3 > 0: a(A008585(n)) = 2; a(A001651(n)) = 0; a(n) mod 3 = 2*(1-A079978(n)). - _Reinhard Zumkeller_, Oct 16 2006
%C A005563 a(n) is the number of divisors of a(n+1) that are not greater than n. - _Reinhard Zumkeller_, Apr 09 2007
%C A005563 Nonnegative X values of solutions to the equation X^3 + X^2 = Y^2. To find Y values: b(n) = n(n+1)(n+2). - _Mohamed Bouhamida_, Nov 06 2007
%C A005563 Sequence allows us to find X values of the equation: X + (X + 1)^2 + (X + 2)^3 = Y^2. To prove that X = n^2 + 2n: Y^2 = X + (X + 1)^2 + (X + 2)^3 = X^3 + 7*X^2 + 15X + 9 = (X + 1)(X^2 + 6X + 9) = (X + 1)*(X + 3)^2 it means: (X + 1) must be a perfect square, so X = k^2 - 1 with k>=1. we can put: k = n + 1, which gives: X = n^2 + 2n and Y = (n + 1)(n^2 + 2n + 3). - _Mohamed Bouhamida_, Nov 12 2007
%C A005563 From _R. K. Guy_, Feb 01 2008: (Start)
%C A005563 Toads and Frogs puzzle:
%C A005563 This is also the number of moves that it takes n frogs to swap places with n toads on a strip of 2n + 1 squares (or positions, or lily pads) where a move is a single slide or jump, illustrated for n = 2, a(n) = 8 by
%C A005563 T T - F F
%C A005563 T - T F F
%C A005563 T F T - F
%C A005563 T F T F -
%C A005563 T F - F T
%C A005563 - F T F T
%C A005563 F - T F T
%C A005563 F F T - T
%C A005563 F F - T T
%C A005563 I was alerted to this by the Holton article, but on consulting Singmaster's sources, I find that the puzzle goes back at least to 1867.
%C A005563 Probably the first to publish the number of moves for n of each animal was Edouard Lucas in 1883. (End)
%C A005563 a(n+1) = terms of rank 0, 1, 3, 6, 10 = A000217 of A120072 (3, 8, 5, 15). - _Paul Curtz_, Oct 28 2008
%C A005563 Row 3 of array A163280, n >= 1. - _Omar E. Pol_, Aug 08 2009
%C A005563 Final digit belongs to a periodic sequence: 0, 3, 8, 5, 4, 5, 8, 3, 0, 9. - _Mohamed Bouhamida_, Sep 04 2009 [Comment edited by _N. J. A. Sloane_, Sep 24 2009]
%C A005563 Let f(x) be a polynomial in x. Then f(x + n*f(x)) is congruent to 0 (mod f(x)); here n belongs to N. There is nothing interesting in the quotients f(x + n*f(x))/f(x) when x belongs to Z. However, when x is irrational these quotients consist of two parts, a) rational integers and b) integer multiples of x. The present sequence represents the non-integer part when the polynomial is x^2 + x + 1 and x = sqrt(2), f(x+n*f(x))/f(x) = A056108(n) + a(n)*sqrt(2). - _A.K. Devaraj_, Sep 18 2009
%C A005563 For n >= 1, a(n) is the number for which 1/a(n) = 0.0101... (A000035) in base (n+1). - _Rick L. Shepherd_, Sep 27 2009
%C A005563 For n > 0, continued fraction [n, 1, n] = (n+1)/a(n); e.g., [6, 1, 6] = 7/48. - _Gary W. Adamson_, Jul 15 2010
%C A005563 Starting (3, 8, 15, ...) = binomial transform of [3, 5, 2, 0, 0, 0, ...]; e.g., a(3) = 15 = (1*3 + 2*5 +1*2) = (3 + 10 + 2). - _Gary W. Adamson_, Jul 30 2010
%C A005563 a(n) is essentially the case 0 of the polygonal numbers. The polygonal numbers are defined as P_k(n) = Sum_{i=1..n} ((k-2)*i-(k-3)). Thus P_0(n) = 2*n-n^2 and a(n) = -P_0(n+2). See also A067998 and for the case k=1 A080956. - _Peter Luschny_, Jul 08 2011
%C A005563 a(n) is the maximal determinant of a 2 X 2 matrix with integer elements from {1, ..., n+1}, so the maximum determinant of a 2x2 matrix with integer elements from {1, ..., 5} = 5^2 - 1 = a(4) = 24. - _Aldo González Lorenzo_, Oct 12 2011
%C A005563 Using four consecutive triangular numbers t1, t2, t3 and t4, plot the points (0, 0), (t1, t2), and (t3, t4) to create a triangle. Twice the area of this triangle are the numbers in this sequence beginning with n = 1 to give 8. - _J. M. Bergot_, May 03 2012
%C A005563 Given a particle with spin S = n/2 (always a half-integer value), the quantum-mechanical expectation value of the square of the magnitude of its spin vector evaluates to <S^2> = S(S+1) = n(n+2)/4, i.e., one quarter of a(n) with n = 2S. This plays an important role in the theory of magnetism and magnetic resonance. - _Stanislav Sykora_, May 26 2012
%C A005563 Twice the harmonic mean [H(x, y) = (2*x*y)/(x + y)] of consecutive triangular numbers A000217(n) and A000217(n+1). - _Raphie Frank_, Sep 28 2012
%C A005563 Number m such that floor(sqrt(m)) = floor(m/floor(sqrt(m))) - 2 for m > 0. - _Takumi Sato_, Oct 10 2012
%C A005563 The solutions of equation 1/(i - sqrt(j)) = i + sqrt(j), when i = (n+1), j = a(n). For n = 1, 2 + sqrt(3) = 3.732050.. = A019973. For n = 2, 3 + sqrt(8) = 5.828427... = A156035. - _Kival Ngaokrajang_, Sep 07 2013
%C A005563 The integers in the closed form solution of a(n) = 2*a(n-1) + a(m-2)*a(n-2), n >= 2, a(0) = 0, a(1) = 1 mentioned by Len Smiley, Dec 08 2001, are m and -m + 2 where m >= 3 is a positive integer. - _Felix P. Muga II_, Mar 18 2014
%C A005563 Let m >= 3 be a positive integer. If a(n) = 2*a(n-1) + a(m-2) * a(n-2), n >= 2, a(0) = 0, a(1) = 1, then lim_{n->oo} a(n+1)/a(n) = m. - _Felix P. Muga II_, Mar 18 2014
%C A005563 For n >= 4 the Szeged index of the wheel graph W_n (with n + 1 vertices). In the Sarma et al. reference, Theorem 2.7 is incorrect. - _Emeric Deutsch_, Aug 07 2014
%C A005563 If P_{k}(n) is the n-th k-gonal number, then a(n) = t*P_{s}(n+2) - s*P_{t}(n+2) for s=t+1. - _Bruno Berselli_, Sep 04 2014
%C A005563 For n >= 1, a(n) is the dimension of the simple Lie algebra A_n. - _Wolfdieter Lang_, Oct 21 2015
%C A005563 Finding all positive integers (n, k) such that n^2 - 1 = k! is known as Brocard's problem, (see A085692). - _David Covert_, Jan 15 2016
%C A005563 For n > 0, a(n) mod (n+1) = a(n) / (n+1) = n. - _Torlach Rush_, Apr 04 2016
%C A005563 Conjecture: When using the Sieve of Eratosthenes and sieving (n+1..a(n)), with divisors (1..n) and n>0, there will be no more than a(n-1) composite numbers. - _Fred Daniel Kline_, Apr 08 2016
%C A005563 a(n) mod 8 is periodic with period 4 repeating (0,3,0,7), that is a(n) mod 8 = 5/2 - (5/2) cos(n*Pi) - sin(n*Pi/2) + sin(3*n*Pi/2). - _Andres Cicuttin_, Jun 02 2016
%C A005563 Also for n > 0, a(n) is the number of times that n-1 occurs among the first (n+1)! terms of A055881. - _R. J. Cano_, Dec 21 2016
%C A005563 The second diagonal of composites (the only prime is number 3) from the right on the Klauber triangle (see Kival Ngaokrajang link), which is formed by taking the positive integers and taking the first 1, the next 3, the following 5, and so on, each centered below the last. - _Charles Kusniec_, Jul 03 2017
%C A005563 Also the number of independent vertex sets in the n-barbell graph. - _Eric W. Weisstein_, Aug 16 2017
%C A005563 Interleaving of A000466 and A033996. - _Bruce J. Nicholson_, Nov 08 2019
%C A005563 a(n) is the number of degrees of freedom in a triangular cell for a Raviart-Thomas or Nédélec first kind finite element space of order n. - _Matthew Scroggs_, Apr 22 2020
%C A005563 From _Muge Olucoglu_, Jan 19 2021: (Start)
%C A005563 For n > 1, a(n-2) is the maximum number of elements in the second stage of the Quine-McCluskey algorithm whose minterms are not covered by the functions of n bits. At n=3, we have a(3-2) = a(1) = 1*(1+2) = 3 and f(A,B,C) = sigma(0,1,2,5,6,7).
%C A005563 .
%C A005563 0 1 2 5 6 7
%C A005563 +---------------
%C A005563 *(0,1)| X X
%C A005563 (0,2)| X X
%C A005563 (1,5)| X X
%C A005563 *(2,6)| X X
%C A005563 *(5,7)| X X
%C A005563 (6,7)| X X
%C A005563 .
%C A005563 *: represents the elements that are covered. (End)
%C A005563 1/a(n) is the ratio of the sum of the first k odd numbers and the sum of the next n*k odd numbers. - _Melvin Peralta_, Jul 15 2021
%C A005563 For n >= 1, the continued fraction expansion of sqrt(a(n)) is [n; {1, 2n}]. - _Magus K. Chu_, Sep 09 2022
%C A005563 Number of diagonals parallel to an edge in a regular (2*n+4)-gon (cf. A367204). - _Paolo Xausa_, Nov 21 2023
%C A005563 For n >= 1, also the number of minimum cyclic edge cuts in the (n+2)-trapezohedron graph. - _Eric W. Weisstein_, Nov 21 2024
%C A005563 For n >= 1, a(n) is the sum of the interior angles of a polygon with n+2 sides, in radians, multiplied by (n+2)/Pi. - _Stuart E Anderson_, Aug 06 2025
%D A005563 E. R. Berlekamp, J. H. Conway and R. K. Guy, Winning Ways, Academic Press, NY, 2 vols., 1982, see index under Toads and Frogs Puzzle.
%D A005563 Martin Gardner, Perplexing Puzzles and Tantalizing Teasers, p. 21 (for "The Dime and Penny Switcheroo").
%D A005563 R. K. Guy, Unsolved Problems in Theory of Numbers, Section D25.
%D A005563 Derek Holton, Math in School, 37 #1 (Jan 2008) 20-22.
%D A005563 Edouard Lucas, Récréations Mathématiques, Gauthier-Villars, Vol. 2 (1883) 141-143.
%D A005563 N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
%H A005563 T. D. Noe, <a href="/A005563/b005563.txt">Table of n, a(n) for n = 0..1000</a>
%H A005563 Jeremiah Bartz, Bruce Dearden, and Joel Iiams, <a href="https://arxiv.org/abs/1810.07895">Classes of Gap Balancing Numbers</a>, arXiv:1810.07895 [math.NT], 2018.
%H A005563 Spencer Daugherty, Pamela E. Harris, Ian Klein, and Matt McClinton, <a href="https://arxiv.org/abs/2406.12941">Metered Parking Functions</a>, arXiv:2406.12941 [math.CO], 2024. See p. 22.
%H A005563 R. K. Guy, <a href="/A005555/a005555.pdf">Letter to N. J. A. Sloane, May 1990</a>.
%H A005563 R. K. Guy, <a href="http://www.cs.uwaterloo.ca/journals/JIS/VOL3/GUY/catwalks.html">Catwalks, sandsteps and Pascal pyramids</a>, J. Integer Sequences, Vol. 3 (2000), Article #00.1.6.
%H A005563 Hsien-Kuei Hwang, S. Janson, and T.-H. Tsai, <a href="http://140.109.74.92/hk/wp-content/files/2016/12/aat-hhrr-1.pdf">Exact and asymptotic solutions of the recurrence f(n) = f(floor(n/2)) + f(ceiling(n/2)) + g(n): theory and applications</a>, Preprint, 2016.
%H A005563 Hsien-Kuei Hwang, S. Janson, and T.-H. Tsai, <a href="https://doi.org/10.1145/3127585">Exact and Asymptotic Solutions of a Divide-and-Conquer Recurrence Dividing at Half: Theory and Applications</a>, ACM Transactions on Algorithms, 13:4 (2017), #47; DOI: 10.1145/3127585.
%H A005563 Milan Janjic, <a href="http://www.pmfbl.org/janjic/">Enumerative Formulas for Some Functions on Finite Sets</a>.
%H A005563 F. P. Muga II, <a href="https://www.researchgate.net/publication/267327689">Extending the Golden Ratio and the Binet-de Moivre Formula</a>, March 2014; Preprint on ResearchGate.
%H A005563 Kival Ngaokrajang, <a href="/A000027/a000027_3.pdf">Klauber triangle</a>
%H A005563 Simon Plouffe, <a href="https://arxiv.org/abs/0911.4975">Approximations de séries génératrices et quelques conjectures</a>, Dissertation, Université du Québec à Montréal, 1992; arXiv:0911.4975 [math.NT], 2009.
%H A005563 Simon Plouffe, <a href="/A000051/a000051_2.pdf">1031 Generating Functions</a>, Appendix to Thesis, Montreal, 1992.
%H A005563 Luis Manuel Rivera, <a href="http://arxiv.org/abs/1406.3081">Integer sequences and k-commuting permutations</a>, arXiv preprint arXiv:1406.3081 [math.CO], 2014.
%H A005563 K. V. S. Sarma and I. V. N. Uma, <a href="http://www.ijma.info/index.php/ijma/article/view/1540">On Szeged index of standard graphs</a>, International J. of Math. Archive, 3(8), 2012, 3129-3135. - _Emeric Deutsch_, Aug 07 2014
%H A005563 Stanislav Sýkora, <a href="http://www.ebyte.it/stan/blog12to14.html#14Dec31">Magnetic Resonance on OEIS</a>, Stan's NMR Blog (Dec 31, 2014), Retrieved Nov 12, 2019.
%H A005563 Leo Tavares, <a href="/A005563/a005563.jpg">Illustration: Bounded Squares</a>.
%H A005563 Leo Tavares, <a href="/A005563/a005563_1.jpg">Illustration: Trapezoids</a>.
%H A005563 Leo Tavares, <a href="/A005563/a005563_2.jpg">Illustration: Trapagons</a>.
%H A005563 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/BarbellGraph.html">Barbell Graph</a>.
%H A005563 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/CyclicEdgeCut.html">Cyclic Edge Cut</a>.
%H A005563 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/IndependentVertexSet.html">Independent Vertex Set</a>.
%H A005563 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/Near-SquarePrime.html">Near-Square Prime</a>.
%H A005563 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/TrapezohedralGraph.html">Trapezohedral Graph</a>.
%H A005563 Wikipedia, <a href="https://en.wikipedia.org/wiki/Quine%E2%80%93McCluskey_algorithm">Quine-McCluskey Algorithm</a>.
%H A005563 <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (3,-3,1).
%F A005563 G.f.: x*(3-x)/(1-x)^3. - _Simon Plouffe_ in his 1992 dissertation
%F A005563 a(n) = A000290(n+1) - 1.
%F A005563 A002378(a(n)) = A002378(n)*A002378(n+1); e.g., A002378(15)=240=12*20. - _Charlie Marion_, Dec 29 2003
%F A005563 a(n) = A067725(n)/3. - _Zerinvary Lajos_, Mar 06 2007
%F A005563 a(n) = Sum_{k=1..n} A144396(k). - _Zerinvary Lajos_, May 11 2007
%F A005563 a(n) = A134582(n+1)/4. - _Zerinvary Lajos_, Feb 01 2008
%F A005563 A143053(a(n)) = A000290(n+1), for n > 0. - _Reinhard Zumkeller_, Jul 20 2008
%F A005563 a(n) = Real((n+1+i)^2). - _Gerald Hillier_, Oct 12 2008
%F A005563 A053186(a(n)) = 2*n. - _Reinhard Zumkeller_, May 20 2009
%F A005563 a(n) = (n! + (n+1)!)/(n-1)!, n > 0. - _Gary Detlefs_, Aug 10 2009
%F A005563 a(n) = floor(n^5/(n^3+1)) with offset 1 (a(1)=0). - _Gary Detlefs_, Feb 11 2010
%F A005563 a(n) = a(n-1) + 2*n + 1 (with a(0)=0). - _Vincenzo Librandi_, Nov 18 2010
%F A005563 Sum_{n>=1} 1/a(n) = 3/4. - _Mohammad K. Azarian_, Dec 29 2010
%F A005563 a(n) = 2/(Integral_{x=0..Pi/2} (sin(x))^(n-1)*(cos(x))^3), for n > 0. - _Francesco Daddi_, Aug 02 2011
%F A005563 a(n) = A002378(n) + floor(sqrt(A002378(n))); pronic number + its root. - _Fred Daniel Kline_, Sep 16 2011
%F A005563 a(n-1) = A008833(n) * A068310(n) for n > 1. - _Reinhard Zumkeller_, Nov 26 2011
%F A005563 G.f.: U(0) where U(k) = -1 + (k+1)^2/(1 - x/(x + (k+1)^2/U(k+1))); (continued fraction, 3-step). - _Sergei N. Gladkovskii_, Oct 19 2012
%F A005563 a(n) = 15*C(n+4,3)*C(n+4,5)/(C(n+4,2)*C(n+4,4)). - _Gary Detlefs_, Aug 05 2013
%F A005563 a(n) = (n+2)!/((n-1)! + n!), n > 0. - _Ivan N. Ianakiev_, Nov 11 2013
%F A005563 a(n) = 3*C(n+1,2) - C(n,2) for n >= 0. - _Felix P. Muga II_, Mar 11 2014
%F A005563 a(n) = (A016742(n+1) - 4)/4 for n >= 0. - _Felix P. Muga II_, Mar 11 2014
%F A005563 a(-2 - n) = a(n) for all n in Z. - _Michael Somos_, Aug 07 2014
%F A005563 A253607(a(n)) = 1. - _Reinhard Zumkeller_, Jan 05 2015
%F A005563 E.g.f.: x*(x + 3)*exp(x). - _Ilya Gutkovskiy_, Jun 03 2016
%F A005563 For n >= 1, a(n^2 + n - 2) = a(n-1) * a(n). - _Miko Labalan_, Oct 15 2017
%F A005563 Sum_{n>=1} (-1)^(n+1)/a(n) = 1/4. - _Amiram Eldar_, Nov 04 2020
%F A005563 From _Amiram Eldar_, Feb 17 2021: (Start)
%F A005563 Product_{n>=1} (1 + 1/a(n)) = 2.
%F A005563 Product_{n>=1} (1 - 1/a(n)) = -sqrt(2)*sin(sqrt(2)*Pi)/Pi. (End)
%F A005563 a(n) = A000290(n+2) - n*2. See Bounded Squares illustration. - _Leo Tavares_, Oct 05 2021
%F A005563 From _Leo Tavares_, Oct 10 2021: (Start)
%F A005563 a(n) = A008585(n) + 2*A000217(n-1). See Trapezoids illustration.
%F A005563 2*A005563 = A054000(n+1). See Trapagons illustration.
%F A005563 a(n) = 2*A000217(n) + n. (End)
%F A005563 a(n) = (n+2)!!/(n-2)!! for n > 1. - _Jacob Szlachetka_, Jan 02 2022
%e A005563 G.f. = 3*x + 8*x^2 + 15*x^3 + 24*x^4 + 35*x^5 + 48*x^6 + 63*x^7 + 80*x^8 + ...
%t A005563 Table[n^2 - 1, {n, 42}] (* _Zerinvary Lajos_, Mar 21 2007 *)
%t A005563 ListCorrelate[{1, 2}, Range[-1, 50], {1, -1}, 0, Plus, Times] (* _Harvey P. Dale_, Aug 29 2015 *)
%t A005563 Range[20]^2 - 1 (* _Eric W. Weisstein_, Aug 16 2017 *)
%t A005563 Table[n (n + 2), {n, 20}] (* _Eric W. Weisstein_, Nov 21 2024 *)
%t A005563 CoefficientList[Series[(-3 + x)/(-1 + x)^3, {x, 0, 20}], x] (* _Eric W. Weisstein_, Nov 21 2024 *)
%t A005563 LinearRecurrence[{3, -3, 1}, {3, 8, 15}, 20] (* _Eric W. Weisstein_, Nov 21 2024 *)
%o A005563 (PARI) a(n)=n*(n+2) \\ _Charles R Greathouse IV_, Dec 22 2011
%o A005563 (PARI) concat(0, Vec(x*(3-x)/(1-x)^3 + O(x^90))) \\ _Altug Alkan_, Oct 22 2015
%o A005563 (Maxima) makelist(n*(n+2), n, 0, 56); /* _Martin Ettl_, Oct 15 2012 */
%o A005563 (Haskell)
%o A005563 a005563 n = n * (n + 2)
%o A005563 a005563_list = zipWith (*) [0..] [2..] -- _Reinhard Zumkeller_, Dec 16 2012
%o A005563 (Magma) [n*(n+2): n in [0..60]]; // _G. C. Greubel_, Mar 29 2024
%o A005563 (SageMath) [n*(n+2) for n in range(61)] # _G. C. Greubel_, Mar 29 2024
%Y A005563 A column of triangle A102537.
%Y A005563 a(n+1), n>=2, first column of triangle A120070.
%Y A005563 Cf. A000035, A000217, A000290, A000466, A001651, A002378, A005563.
%Y A005563 Cf. A007531, A008585, A008833, A013468, A016742, A019973, A028560.
%Y A005563 Cf. A033996, A046092, A053186, A054000, A055881, A056108, A062196.
%Y A005563 Cf. A068310, A067725, A067728, A067998, A069817, A079978, A080956.
%Y A005563 Cf. A085692, A120072, A123865, A123866, A123867, A123868, A134582.
%Y A005563 Cf. A140091, A140681, A143053, A144396, A156035, A163280, A212331.
%Y A005563 Cf. A253607, A367204.
%K A005563 nonn,easy
%O A005563 0,2
%A A005563 _N. J. A. Sloane_
%E A005563 Partially edited by _Joerg Arndt_, Mar 11 2010
%E A005563 More terms from _N. J. A. Sloane_, Aug 01 2010