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A016827 a(n) = (4n+2)^3.

%I A016827 #34 Jul 08 2025 05:55:52
%S A016827 8,216,1000,2744,5832,10648,17576,27000,39304,54872,74088,97336,
%T A016827 125000,157464,195112,238328,287496,343000,405224,474552,551368,
%U A016827 636056,729000,830584,941192,1061208,1191016
%N A016827 a(n) = (4n+2)^3.
%H A016827 Michael De Vlieger, <a href="/A016827/b016827.txt">Table of n, a(n) for n = 0..10000</a>
%H A016827 <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4,-6,4,-1).
%F A016827 G.f.: 8*(1 + 23*x + 23*x^2 + x^3)/(1 - x)^4. - _Ilya Gutkovskiy_, Jun 21 2016
%F A016827 From _Amiram Eldar_, Jun 28 2020: (Start)
%F A016827 Sum_{n>=0} 1/a(n) = 7*zeta(3)/64.
%F A016827 Sum_{n>=0} (-1)^n/a(n) = Pi^3/256. (End)
%F A016827 a(n) = 4*a(n-1)-6*a(n-2)+4*a(n-3)-a(n-4). - _Wesley Ivan Hurt_, Mar 08 2022
%t A016827 Table[(4n+2)^3,{n,0,100}] (* _Mohammad K. Azarian_, Jun 20 2016 *)
%Y A016827 Odd bisection of A016743.
%Y A016827 Subsequence of A000578.
%K A016827 nonn,easy
%O A016827 0,1
%A A016827 _N. J. A. Sloane_