A022935 a(n) = a(n-1) + c(n-1) for n >= 2, a( ) increasing, given a(1)=3, where c( ) is complement of a( ).
3, 4, 6, 11, 18, 26, 35, 45, 57, 70, 84, 99, 115, 132, 151, 171, 192, 214, 237, 261, 286, 313, 341, 370, 400, 431, 463, 496, 530, 566, 603, 641, 680, 720, 761, 803, 846, 890, 936, 983, 1031, 1080, 1130, 1181, 1233, 1286, 1340, 1395, 1451, 1509
Offset: 1
Keywords
Links
- Vincenzo Librandi, Table of n, a(n) for n = 1..1000
Programs
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Mathematica
mex := First[Complement[Range[1, Max[#1] + 1], #1]] &; a[1] = 3; c[1] = 1; c[2] = 2; a[n_] := a[n] = a[n - 1] + c[n - 1]; c[n_] := c[n] = mex[Flatten[Table[{a[i], c[i]}, {i, 1, n - 1}]]]; Table[a[n], {n, 80}] (* A022935 *) Table[c[n], {n, 80}] (* Clark Kimberling, May 15 2012 *)
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