A023397 In base 10, if any power of 2 ends with k 2's and 3's, they must be the first k terms of this sequence in reverse order.
2, 3, 2, 3, 2, 2, 2, 3, 2, 3, 2, 3, 3, 2, 3, 3, 3, 3, 3, 3, 2, 3, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 2, 3, 3, 2, 3, 3, 3, 3, 3, 2, 2, 2, 2, 3, 3, 2, 3, 2, 2, 3, 2, 2, 3, 2, 2, 3, 2, 2, 2, 2, 3, 2, 2, 3, 2, 3, 3, 3, 2, 2, 3, 3, 3, 2, 3, 3, 3, 2, 2, 2, 2, 2, 3, 2, 2, 3, 3, 3, 2, 3, 2, 3, 3, 2, 3, 2, 3, 3, 2, 2, 2, 2, 2, 3, 2
Offset: 1
Examples
No power of 2 ends with 3, so the first term is 2. No power of 2 is == 22 (mod 100), since 4 does not divide 22, so the next term is 3 (and 4 does divide 32). No power of 2 is == 332 (mod 1000), since 8 does not divide 332, so the next term is 2 (and 8 does divide 232). And so on.
Links
- Ray Chandler, Table of n, a(n) for n = 1..10000