A024667 a(n) = position of 2*n^3 in A003325.
1, 3, 6, 11, 18, 25, 33, 44, 57, 68, 81, 99, 116, 134, 152, 177, 200, 223, 246, 276, 304, 331, 360, 397, 433, 465, 501, 541, 579, 617, 662, 707, 749, 793, 845, 895, 944, 995, 1051, 1105, 1161, 1214, 1279, 1337, 1397, 1456, 1528, 1591, 1657, 1722, 1799, 1870
Offset: 1
Keywords
Links
- Robert Israel, Table of n, a(n) for n = 1..2000
Crossrefs
Cf. A003325.
Programs
-
Maple
M:= 200: # to get a(1) .. a(M) N:= 2*N^3: A:=sort(convert({seq(seq(x^3 + y^3, y = 1 .. floor((N-x^3)^(1/3))),x=1..floor(N^(1/3)))},list)): filter:= proc(n) local F; if n::odd then return false fi; F:= ifactors(n/2)[2][..,2] mod 3; andmap(`=`,F,0) end proc: select(t -> filter(A[t]), [$1..nops(A)]); # Robert Israel, Sep 19 2024
Formula
It appears that a(n) ~ 2^(2/3) * Pi^2 * n^2/(9 * Gamma(2/3)^3). - Robert Israel, Sep 19 2024