A044873 -id:A044873 - cp's OEIS frontend

A044879 Numbers having, in base 8, (sum of even run lengths)=(sum of odd run lengths).

513, 514, 515, 516, 517, 518, 519, 521, 530, 539, 548, 557, 566, 575, 577, 578, 579, 580, 581, 582, 583, 592, 593, 595, 596, 597, 598, 599, 600, 601, 602, 604, 605, 606, 607, 608, 609, 610, 611, 613, 614, 615, 616, 617, 618

Offset: 1

Clark Kimberling

Cf. A007094.
Cf. A044873, A044874, A044875, A044876, A044877, A044878, A044880.
Cf. A044881, A044882, A044883, A044884, A044885, A044886, A044887.

from itertools import groupby
def ok(n):
    rl_sums = [0, 0]
    for k, g in groupby(oct(n)[2:]):
        rl = len(list(g))
        rl_sums[rl%2] += rl
    return rl_sums[0] == rl_sums[1]
print(list(filter(ok, range(619)))) # Michael S. Branicky, Sep 11 2021

A044881 Numbers having, in base 10, (sum of even run lengths)=(sum of odd run lengths).

Original entry on oeis.org

1001, 1002, 1003, 1004, 1005, 1006, 1007, 1008, 1009, 1011, 1022, 1033, 1044, 1055, 1066, 1077, 1088, 1099, 1101, 1102, 1103, 1104, 1105, 1106, 1107, 1108, 1109, 1120, 1121, 1123, 1124, 1125, 1126, 1127, 1128, 1129

Offset: 1

Clark Kimberling

Cf. A000027.
Cf. A044873, A044874, A044875, A044876, A044877, A044878, A044879.
Cf. A044880, A044882, A044883, A044884, A044885, A044886, A044887.

from itertools import groupby
def ok(n):
    rl_sums = [0, 0]
    for k, g in groupby(str(n)):
        rl = len(list(g))
        rl_sums[rl%2] += rl
    return rl_sums[0] == rl_sums[1]
print(list(filter(ok, range(1130)))) # Michael S. Branicky, Sep 11 2021

A044887 Numbers having, in base 16, (sum of even run lengths)=(sum of odd run lengths).

Original entry on oeis.org

4097, 4098, 4099, 4100, 4101, 4102, 4103, 4104, 4105, 4106, 4107, 4108, 4109, 4110, 4111, 4113, 4130, 4147, 4164, 4181, 4198, 4215, 4232, 4249, 4266, 4283, 4300, 4317, 4334, 4351, 4353, 4354, 4355, 4356, 4357, 4358

Offset: 1

Clark Kimberling

Cf. A104619.
Cf. A044873, A044874, A044875, A044876, A044877, A044878, A044879.
Cf. A044880, A044881, A044882, A044883, A044884, A044885, A044886.

from itertools import groupby
def ok(n):
    rl_sums = [0, 0]
    for k, g in groupby(hex(n)[2:]):
        rl = len(list(g))
        rl_sums[rl%2] += rl
    return rl_sums[0] == rl_sums[1]
print(list(filter(ok, range(4359)))) # Michael S. Branicky, Sep 11 2021

cp's OEIS Frontend

A044879 Numbers having, in base 8, (sum of even run lengths)=(sum of odd run lengths).

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A044881 Numbers having, in base 10, (sum of even run lengths)=(sum of odd run lengths).

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Python

A044887 Numbers having, in base 16, (sum of even run lengths)=(sum of odd run lengths).

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Python