A044881 Numbers having, in base 10, (sum of even run lengths)=(sum of odd run lengths).

1001, 1002, 1003, 1004, 1005, 1006, 1007, 1008, 1009, 1011, 1022, 1033, 1044, 1055, 1066, 1077, 1088, 1099, 1101, 1102, 1103, 1104, 1105, 1106, 1107, 1108, 1109, 1120, 1121, 1123, 1124, 1125, 1126, 1127, 1128, 1129

Offset: 1

Author

Clark Kimberling

Keywords

• nonn
• base

Crossrefs

Cf. A000027.

Cf. A044873, A044874, A044875, A044876, A044877, A044878, A044879.

Cf. A044880, A044882, A044883, A044884, A044885, A044886, A044887.

Programs

Python

from itertools import groupby
def ok(n):
    rl_sums = [0, 0]
    for k, g in groupby(str(n)):
        rl = len(list(g))
        rl_sums[rl%2] += rl
    return rl_sums[0] == rl_sums[1]
print(list(filter(ok, range(1130)))) # Michael S. Branicky, Sep 11 2021