A055077 Multiplicity of Max{gcd(d, n!/d)} when d runs over the divisors of n!.
1, 2, 4, 4, 8, 2, 4, 8, 8, 2, 4, 8, 16, 16, 16, 16, 32, 16, 32, 16, 64, 64, 128, 32, 32, 32, 64, 32, 64, 32, 64, 128, 512, 128, 128, 128, 256, 256, 256, 256, 512, 1024, 2048, 1024, 512, 128, 256, 128, 128, 256, 1024, 512, 1024, 256, 1024, 4096, 16384, 4096, 8192
Offset: 1
Keywords
Examples
n=5, 5!=120, the set of gcd(d, 120/d) values for the 16 divisors of 120 is {1,2,1,2,1,2,1,2,2,1,2,1,2,1,2,1}. The maximum is 2 and it occurs 8 times, so a(5)=8.
Crossrefs
Cf. A000188.
Programs
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Mathematica
Table[Count[#, Max@ #] &@ Map[GCD[#, m/#] &, Divisors[m]], {m, Range[30]!}] (* Michael De Vlieger, Oct 06 2019 *)
Formula
It appears that a(n) = 2^A055460(n). - Joerg Arndt, Oct 06 2019
Comments