A055191 Cumulative counting sequence: method A (adjective-before-noun) pairs, starting with 5.

5, 1, 5, 2, 5, 1, 1, 3, 5, 3, 1, 1, 2, 4, 5, 5, 1, 2, 2, 2, 3, 6, 5, 6, 1, 5, 2, 3, 3, 1, 4, 8, 5, 8, 1, 6, 2, 5, 3, 2, 4, 2, 6, 10, 5, 9, 1, 9, 2, 6, 3, 3, 4, 4, 6, 2, 8, 11, 5, 10, 1, 11, 2, 8, 3, 5, 4, 6, 6, 3, 8, 1, 10, 2, 9, 13, 5, 12, 1, 13, 2, 10, 3, 6, 4, 8

Offset: 1

Author

Clark Kimberling, Apr 27 2000

Keywords

• nonn

Comments

Segments (generated as at A217760): 5; 1,5; 2,5,1,1; 3,5,3,1,1,2; ... The 4th segment is read "3 5's and 3 1's and 1 2" as a record of what was previously written; 3,3,1 are adjectives and 5 1 2 are nouns. Conjecture: every nonnegative integer occurs. - Clark Kimberling, Mar 25 2013

Examples

			Write 5, thus having 1 5, thus having 2 5's and 1 1, thus having 3 5's and 3 1's and 1 2, etc.
		

Links

• Seiichi Manyama, Table of n, a(n) for n = 1..10000

Crossrefs

Cf. A217760, A217780.

Programs

Mathematica

s = {5}; Do[s = Flatten[{s, {Count[s, #], #} & /@ DeleteDuplicates[s]}], {14}]; s (* Peter J. C. Moses, Mar 21 2013 *)