A056177 Sum of a(n) terms of 1/k^(1/5) first exceeds n.
1, 2, 3, 4, 5, 7, 8, 10, 11, 13, 15, 16, 18, 20, 22, 24, 26, 28, 29, 31, 33, 36, 38, 40, 42, 44, 46, 48, 50, 53, 55, 57, 59, 62, 64, 66, 68, 71, 73, 75, 78, 80, 83, 85, 88, 90, 92, 95, 97, 100, 102, 105, 108, 110, 113, 115, 118, 120, 123, 126, 128, 131, 134, 136, 139
Offset: 0
Keywords
Crossrefs
Cf. A019529.
Programs
-
Mathematica
s = 0; k = 1; Do[ While[ s <= n, s = s + N[ 1/k^(1/5), 24 ]; k++ ]; Print[ k - 1 ], {n, 1, 75} ]