A057030 Let P(n) of a sequence s(1),s(2),s(3),... be obtained by leaving s(1),...,s(n-1) fixed and reversing every n consecutive terms thereafter; apply P(2) to 1,2,3,... to get PS(2), then apply P(3) to PS(2) to get PS(3), then apply P(4) to PS(3), etc. The limit of PS(n) is A057030.

1, 3, 4, 6, 11, 13, 14, 22, 27, 29, 40, 42, 47, 55, 66, 68, 83, 85, 86, 110, 115, 123, 138, 140, 161, 179, 180, 182, 223, 231, 236, 270, 275, 277, 314, 332, 337, 371, 382, 384, 425, 427, 438, 472, 477, 537, 542, 550, 555, 619, 630

Offset: 1

Author

Clark Kimberling, Jul 29 2000

Keywords

• nonn
• nice
• easy

Examples

			PS(2) begins with 1,3,2,5,4,7,6;
PS(3) begins with 1,3,4,5,2,9,6;
PS(4) begins with 1,3,4,6,9,2,5.
		

Links

• Peter J. C. Moses, Table of n, a(n) for n = 1..5000

Crossrefs

Cf. A007062, A057032, A057033, A057063, A057064.

Programs

Mathematica

a057030=Range[x=3500]; Do[a057030=Flatten[Join[{Take[a057030,n-1]},Map[Reverse,Partition[Drop[a057030,n-1],n]]]],{n,2,NestWhile[#+1&,1,(x=# Floor[x/#])>0&]-1}]; a057030 (* Peter J. C. Moses, Nov 10 2016 *)

Formula

Conjecture: a(n) = A007062(n+1) - 1 for n > 0. - Mikhail Kurkov, Mar 10 2022