A308437 Triangle read by rows: T(n,k) = number of ways, summed over the free n-ominoes, that an n-omino with an assigned orientation can be maximally (partially) covered by k X 1 tiles.
1, 1, 1, 2, 4, 1, 5, 8, 4, 1, 12, 35, 18, 4, 1, 35, 89, 61, 22, 5, 1, 108, 425, 206, 97, 28, 5, 1, 369, 1438, 739, 436, 141, 36, 6, 1, 1285, 6818, 3008, 1853, 687, 193, 44, 6, 1, 4655, 27713, 12823, 7668, 3233, 1039, 268, 54, 7, 1, 17073, 125830, 51619, 30902, 14731, 5164, 1518, 351, 64, 7, 1
Offset: 1
Examples
The triangle starts with n >= 1, 1 <= k <= n as follows: 1; 1, 1; 2, 4, 1; 5, 8, 4, 1; 12, 35, 18, 4, 1; 35, 89, 61, 22, 5, 1; 108, 425, 206, 97, 28, 5, 1; 369, 1438, 739, 436, 141, 36, 6, 1; 1285, 6818, 3008, 1853, 687, 193, 44, 6, 1; (...) From _M. F. Hasler_ and _R. J. Mathar_, May 27 2019: (Start) We have T(n,1) = A000105(n) which is the number of different inequivalent n-ominoes, and each one can be maximally filled in exactly one (trivial) way with 1 X 1 monominoes. We have T(n,n) = 1 because only the straight n X 1 polyomino can be filled in the required way, namely with only straight n-ominoes. T(3,2) = 4 counts 2 ways of placing a domino into the straight tromino (the two ends of the tromino considered distinct) and 2 ways of placing a domino into the L-tromino (again the two variants obtained by flipping along the diagonal considered distinct). (End)
Links
Formula
T(n,1) = A000105(n).
T(n,n) = 1.
Extensions
NAME improved, Peter Munn, May 30 2019
Comments