cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A059797 Second in a series of arrays counting standard tableaux by partition type.

Original entry on oeis.org

2, 5, 5, 9, 16, 9, 14, 35, 35, 14, 20, 64, 90, 64, 20, 27, 105, 189, 189, 105, 27, 35, 160, 350, 448, 350, 160, 35, 44, 231, 594, 924, 924, 594, 231, 44, 54, 320, 945, 1728, 2100, 1728, 945, 320, 54, 65, 429, 1430, 3003, 4290, 4290, 3003, 1430, 429, 65
Offset: 0

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Author

Alford Arnold, Feb 22 2001

Keywords

Comments

The first array in the series is Pascal's triangle, A007318. The initial partition for each subsequent array in the series is chosen as described in A053445. When cells are squared, as in A008459, row sums yield 1, 2, 6, 24, ... (A000142). E.g., (1 + 16 + 36 + 16 + 1) + (25 + 25) = 70 + 50 = 120 using row five from A007318 and row two from this array.
Number of lattice paths from (0,0) to (n,k) in exactly n+k+2 steps. Moves allowed: (0,1), (0,-1), (-1,0) and (1,0). Paths must stay in Quadrant I but may touch the axes. - Juan Luis Vargas-Molina, Mar 03 2014

Examples

			a(5) = 16 because we can write T(2,2) = T(1,2) + T(1,1) + A007318(4,2) = 5 + 5 + 6.
   2;
   5,   5;
   9,  16,   9;
  14,  35,  35,  14;
  20,  64,  90,  64,  20;
  27, 105, 189, 189, 105,  27;
T(n,k) as a grid for the first few lattice points. Where T(0,0)=2 since there are two ways to get to (0,0) with "0+0+2" steps under the move restrictions.
     k = 0  1   2   3    4    5
T(0,k) = 2  5   9   14   20   27
T(1,k) = 5  16  35  64   105  160
T(2,k) = 9  35  90  189  350  594
T(3,k) = 14 64  189 448  924  1728
T(4,k) = 20 105 350 924  2100 4290
T(5,k) = 27 160 594 1728 4290 9504
- _Juan Luis Vargas-Molina_, Mar 03 2014
		

References

  • Stanton and White, Constructive Combinatorics, 1986, pp. 84, 91.

Crossrefs

Programs

  • Maple
    A059797 := proc(n,k) option remember; if n <0 or k<0 or k>n then 0; else procname(n-1,k-1)+procname(n-1,k)+binomial(n+2,k+1) ; end if; end proc:
    seq(seq( A059797(n,k),k=0..n),n=0..15) ; # R. J. Mathar, Jan 27 2011
  • Mathematica
    t[n_, k_] /; (n < 0 || k < 0 || k > n) = 0; t[n_, k_] := t[n, k] = t[n - 1, k - 1] + t[n - 1, k] + Binomial[n + 2, k + 1]; Flatten[ Table[ t[n, k], {n, 0, 9}, {k, 0, n}]] (* Jean-François Alcover, Dec 20 2011, after R. J. Mathar *)
    T[n_, k_] := (k + 1)(n + k +4) FactorialPower[k + n + 2, n]/(n! + (n + 1)!)
    MatrixForm[Table[T[n, k], {n, 0, 10}, {k, 0, 10}]] (* Juan Luis Vargas-Molina, Mar 03 2014 *)

Formula

T(row, col) = T(row-1, col-1) + T(row-1, col) + A007318(row+2, col+1). - Corrected by R. J. Mathar, Jan 27 2011
T(n,k) = (k+1)(n+k+4)FallingFactorial(n+k+2,n)/((n+1)!+n!) n,k >= 0. - Juan Luis Vargas-Molina, Mar 03 2014