A060334 The sequence A006863 (shifted by one) seems to be counting the periodic points for a map. If so, then this is the sequence of the numbers of orbits of length n.
24, 108, 160, 60, 48, 10800, 0, 1980, 3136, 1272, 48, 5440, 0, 480, 11408, 1020, 0, 7671552, 0, 53448, 7200, 216, 48, 179520, 0, 480, 2128, 240, 48, 227138600, 0
Offset: 1
Examples
a(3) = 160 because the 4th term of A006863 is 504 and the 2nd term is 24, so there should be (504-24)/3 = 160 orbits of length 3.
Links
- Y. Puri and T. Ward, Arithmetic and growth of periodic orbits, J. Integer Seqs., Vol. 4 (2001), #01.2.1.
- T. Ward, Exactly realizable sequences
Formula
If b(n) is the (n+1)st term of A006863, then a(n)=(1/n)* Sum_{d|n}\mu(d)b(n/d)