cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A063736 Patterns of possible squarefree triples of 3 consecutive numbers {4k+1, 4k+2, 4k+3} are coded as follows: compute A008966(x) getting one of {000, 001, 010, 011, 100, 101, 110, 111} and convert to decimal.

Original entry on oeis.org

7, 7, 3, 7, 5, 7, 2, 7, 7, 7, 7, 3, 1, 5, 7, 6, 7, 7, 6, 7, 3, 7, 5, 7, 4, 7, 7, 7, 7, 3, 3, 1, 7, 6, 7, 7, 6, 5, 3, 7, 5, 7, 2, 6, 7, 7, 7, 3, 7, 5, 7, 6, 7, 7, 7, 7, 3, 7, 5, 7, 4, 3, 5, 7, 7, 3, 7, 5, 6, 6, 7, 7, 3, 5, 3, 7, 5, 7, 6, 7, 7, 3, 7, 3, 5, 4, 7, 4, 7, 7, 2, 7, 3, 6, 5, 7, 6, 7, 7, 7, 7, 3, 7, 5, 7
Offset: 0

Views

Author

Labos Elemer, Aug 24 2001

Keywords

Comments

All code values arise corresponding to 8 classes of patterns. E.g., the first nonsquarefree triple (000 pattern, code=0) appears at 844, [845, 846, 847], 848 as a middle part of a nonsquarefree 5-tuple. Start values of code=7 triples are listed in A063238.

Examples

			a(0) = 4*A008966(1)+2*A008966(2)+A008966(3) = 4+2+1 = 7.
a(11) = 4*A008966(45)+2*A008966(46)+A008966(47) = 0+2+1 = 3.
a(12) = 4*A008966(49)+2*A008966(50)+A008966(51) = 0+0+1 = 1.
a(13) = 4*A008966(53)+2*A008966(54)+A008966(55) = 4+0+1 = 5.
a(14) = 4*A008966(57)+2*A008966(58)+A008966(59) = 4+2+1 = 7.
		

Crossrefs

Formula

a(n) = 4*A008966(4n+1)+2*A008966(4n+2)+A008966(4n+3).