A069962 - cp's OEIS frontend

A069962 Define C(n) by the recursion C(0) = 5i where i^2 = -1, C(n+1) = 1/(1 + C(n)), then a(n) = 5(-1)^n/Im(C(n)) where Im(z) denotes the imaginary part of z.

n	a(n)
0	1
1	26
2	29
3	109
4	250
5	689
6	1769
7	4666
8	12181
9	31925
10	83546
11	218761
12	572689
13	1499354
14	3925325
15	10276669
16	26904634
17	70437281
18	184407161
19	482784250
20	1263945541
21	3309052421
22	8663211674
23	22680582649
24	59378536225
25	155455026074
26	406986541949
27	1065504599821

[1, 26, 29, 109, 250, 689, 1769, 4666, 12181, 31925, 83546, 218761, 572689, 1499354, 3925325, 10276669, 26904634, 70437281, 184407161, 482784250, 1263945541, 3309052421, 8663211674, 22680582649, 59378536225, 155455026074, 406986541949, 1065504599821]

cp's OEIS Frontend

A069962 Define C(n) by the recursion C(0) = 5i where i^2 = -1, C(n+1) = 1/(1 + C(n)), then a(n) = 5(-1)^n/Im(C(n)) where Im(z) denotes the imaginary part of z.

Table of values

List of values

cp's OEIS Frontend

A069962 Define C(n) by the recursion C(0) = 5*i where i^2 = -1, C(n+1) = 1/(1 + C(n)), then a(n) = 5*(-1)^n/Im(C(n)) where Im(z) denotes the imaginary part of z.

Table of values

List of values

A069962 Define C(n) by the recursion C(0) = 5i where i^2 = -1, C(n+1) = 1/(1 + C(n)), then a(n) = 5(-1)^n/Im(C(n)) where Im(z) denotes the imaginary part of z.