A079945 Partial sums of A079882.

1, 3, 4, 5, 7, 9, 10, 11, 12, 13, 15, 17, 19, 21, 22, 23, 24, 25, 26, 27, 28, 29, 31, 33, 35, 37, 39, 41, 43, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 63, 65, 67, 69, 71, 73, 75, 77, 79, 81, 83, 85, 87, 89, 91, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102, 103

Offset: 0

Author

N. J. A. Sloane, Feb 21 2003

Keywords

• nonn
• look

References

• Hsien-Kuei Hwang, S Janson, TH Tsai, Exact and asymptotic solutions of the recurrence f(n) = f(floor(n/2)) + f(ceiling(n/2)) + g(n): theory and applications, Preprint, 2016; http://140.109.74.92/hk/wp-content/files/2016/12/aat-hhrr-1.pdf. Also Exact and Asymptotic Solutions of a Divide-and-Conquer Recurrence Dividing at Half: Theory and Applications, ACM Transactions on Algorithms, 13:4 (2017), #47; DOI: 10.1145/3127585

Links

• Robert Israel, Table of n, a(n) for n = 0..10000
• R. Stephan, Some divide-and-conquer sequences ...
• R. Stephan, Table of generating functions

Crossrefs

Apart from initial terms, same as A080596.

Programs

Maple

A079882:= [seq(op([1$(2^n),2$(2^n)]),n=0..6)]:
ListTools:-PartialSums(A079882); # Robert Israel, Oct 26 2020

Formula

See A080596 for an explicit formula.

a(n) = (3*n+3-2^(A000523((n+2)/2))-(-1)^A079944(n)*(n+3-3*2^(A000523((n+2)/2))))/2. - Antonio G. Astudillo (afg_astudillo(AT)hotmail.com), Feb 23 2003

Also a(n) = n+2^A000523((n+2)/2)*(1-3*A079944(n))+A079944(n)*(n+3) - Antonio G. Astudillo (afg_astudillo(AT)hotmail.com), Feb 23 2003