cp's OEIS Frontend

A080094 Let sum(k>=0, k^n/(2*k+1)!) = (x(n)*e + y(n)/e)/z(n), where x(n) and z(n) are >0, then a(n)=y(n).

%I A080094 #7 Mar 30 2012 18:39:15
%S A080094 1,-3,3,-1,3,-5,-2,-5,55,106,201,-2381,-7675,-35183,145359,910719,
%T A080094 8117231,521487,-139498274,-2261959961,-7554900397,17363594398,
%U A080094 690775844605,4901767330647,5460910088617,-179314430713387,-2668801066419061,-9075259309421889,-20645060784367893
%N A080094 Let sum(k>=0, k^n/(2*k+1)!) = (x(n)*e + y(n)/e)/z(n), where x(n) and z(n) are >0, then a(n)=y(n).
%Y A080094 Cf. A080093, A080095.
%K A080094 sign
%O A080094 1,2
%A A080094 _Benoit Cloitre_ and _Paul D. Hanna_, Jan 28 2003