A081837 - cp's OEIS frontend

A081837 Let z(n) be e = exp(1.0) = 2.7182.... truncated to n decimal digits after the decimal point; sequence gives maximum element in the continued fraction for z(n).

n	a(n)
0	2
1	3
2	4
3	12
4	9
5	10
6	12
7	11
8	9
9	10
10	8
11	22
12	13
13	13
14	15
15	12
16	35
17	30
18	48
19	18
20	166
21	166
22	68
23	40
24	73
25	137
26	57
27	1288
28	62
29	28
30	416
31	552
32	138
33	47
34	24
35	156
36	110
37	31
38	463
39	85
40	108
41	106
42	295
43	295
44	54
45	98
46	40
47	388
48	216
49	32
50	49
51	199
52	488
53	47
54	64
55	822
56	51
57	152
58	854
59	38
60	701
61	88
62	94
63	149

[2, 3, 4, 12, 9, 10, 12, 11, 9, 10, 8, 22, 13, 13, 15, 12, 35, 30, 48, 18, 166, 166, 68, 40, 73, 137, 57, 1288, 62, 28, 416, 552, 138, 47, 24, 156, 110, 31, 463, 85, 108, 106, 295, 295, 54, 98, 40, 388, 216, 32, 49, 199, 488, 47, 64, 822, 51, 152, 854, 38, 701, 88, 94, 149]

cp's OEIS Frontend

A081837 Let z(n) be e = exp(1.0) = 2.7182.... truncated to n decimal digits after the decimal point; sequence gives maximum element in the continued fraction for z(n).

Table of values

List of values