A083075 Square array read by antidiagonals: T(n,k) = (k*(2*k+3)^n + 1)/(k+1).
1, 1, 1, 1, 3, 1, 1, 5, 13, 1, 1, 7, 33, 63, 1, 1, 9, 61, 229, 313, 1, 1, 11, 97, 547, 1601, 1563, 1, 1, 13, 141, 1065, 4921, 11205, 7813, 1, 1, 15, 193, 1831, 11713, 44287, 78433, 39063, 1, 1, 17, 253, 2893, 23801, 128841, 398581, 549029, 195313, 1, 1, 19, 321
Offset: 0
Examples
Array begins: 1 1 1 1 1 ... 1 3 13 63 313 ... 1 5 33 229 1601 ... 1 7 61 547 4921 ... 1 9 97 1065 11713 ... ...
Links
- Nathaniel Johnston, Antidiagonals 0..100, flattened
Crossrefs
Programs
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Maple
T := proc(n,k) return (k*(2*k+3)^n+1)/(k+1): end: seq(seq(T(k,n-k),k=0..n),n=0..10); # Nathaniel Johnston, Jun 26 2011