A084019 a(n) = 9's complement of n-th palindrome (A002113).

9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 88, 77, 66, 55, 44, 33, 22, 11, 0, 898, 888, 878, 868, 858, 848, 838, 828, 818, 808, 797, 787, 777, 767, 757, 747, 737, 727, 717, 707, 696, 686, 676, 666, 656, 646, 636, 626, 616

Offset: 1

Author

Amarnath Murthy and Meenakshi Srikanth (menakan_s(AT)yahoo.com), May 23 2003

Keywords

• base
• easy
• nonn

Comments

Leading zeros in the 9's complement are omitted.

For palindromes of the form 10^k-1 the corresponding entry is zero. Apart from this the entries are distinct.

Examples

			The 20th palindromic number A002113(20) is 101 having 9's complement 898 (999 - 101 = 898). So a(20) = 898. - _Indranil Ghosh_, Jan 30 2017
		

Links

• Indranil Ghosh, Table of n, a(n) for n = 1..25000

Crossrefs

Cf. A002113, A061601, A084020.

Programs

Python

# Program for generating the b-file
def a(n):
    return 10**len(str(n))-n-1
i=0
j=1
while j<=250:
    if i==int(str(i)[::-1]):
        print(str(j)+" "+str(a(i)))
        j+=1
    i+=1 # Indranil Ghosh, Jan 30 2017

Python

def A084019(n):
    if n == 1: return 9
    y = 10*(x:=10**(len(str(n>>1))-1))
    if nChai Wah Wu, Jun 13 2024