A091532 Where the number of terms in simple continued fraction for H(j) exceeds all H(i), j>i and H(k) is the k-th harmonic number.
1, 2, 3, 5, 7, 8, 9, 13, 16, 17, 19, 23, 25, 26, 28, 29, 35, 36, 43, 45, 48, 49, 54, 57, 62, 72, 73, 79, 88, 90, 91, 99, 103, 108, 110, 113, 115, 116, 118, 125, 128, 148, 149, 157, 163, 168, 171, 172, 184, 193, 199, 205, 209, 234, 240, 243, 259, 265, 269, 270, 281, 283
Offset: 1
Keywords
Links
- Amiram Eldar, Table of n, a(n) for n = 1..4000
Programs
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Mathematica
t = Table[ Length[ ContinuedFraction[ HarmonicNumber[n]]], {n, 1, 299}]; a = {1}; Do[ If[ t[[n]] > t[[a[[ -1]]]], AppendTo[a, n]], {n, 1, 299}]; a
Comments