A092142 Compute the continued fraction expansion of Pi; multiply each term by i, the square root of -1, compute this new continued fraction and get a number with a real part equal to 0. Then compute the regular continued fraction of the imaginary part of that new number.

2, 1, 5, 1, 12, 1, 301, 2, 78, 1, 14, 1, 1, 1, 10, 1, 1, 2, 4, 1, 4, 1, 94, 1, 3, 1, 1, 1, 8, 1, 5, 1, 2, 2, 4, 1, 10, 1, 8, 1, 10, 1, 13, 1, 158, 1, 42, 1, 18, 1, 21, 1, 8, 2, 2, 1, 3, 1, 2, 3, 23, 1, 8, 2, 39, 1, 3, 1, 1, 1, 7, 2, 2, 1, 7, 1, 5, 3, 53, 1, 14, 1, 6, 1, 15, 1, 14, 2, 5, 1, 28, 1, 1, 2, 4

Offset: 0

Author

Thomas Baruchel, Mar 31 2004

Keywords

• easy
• nonn

Programs

PARI

k=contfracpnqn(contfrac(Pi,500)*I);contfrac(imag(k[1,1]/k[2,1]),200)