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A092846 a(n) = 100...001^n, where there are just enough zeros for the result to display the terms in the n-th row of Pascal's triangle.

%I A092846 #8 Jan 21 2019 19:01:55
%S A092846 1,11,121,1331,14641,10510100501,1061520150601,107213535210701,
%T A092846 10828567056280801,1009036084126126084036009001,
%U A092846 1010045120210252210120045010001,1011055165330462462330165055011001,1012066220495792924792495220066012001
%N A092846 a(n) = 100...001^n, where there are just enough zeros for the result to display the terms in the n-th row of Pascal's triangle.
%H A092846 Eric M. Schmidt, <a href="/A092846/b092846.txt">Table of n, a(n) for n = 0..50</a>
%F A092846 a(n) = (10^k + 1)^n, where k is the number of digits in A001405(n). - _Eric M. Schmidt_, Apr 04 2014
%e A092846 a(0)=11^0
%e A092846 a(1)=11^1
%e A092846 a(2)=11^2
%e A092846 a(3)=11^3
%e A092846 a(4)=11^4
%e A092846 a(5)=101^5
%e A092846 a(6)=101^6
%e A092846 a(7)=101^7
%e A092846 a(8)=101^8
%e A092846 a(9)=1001^9
%e A092846 a(10)=1001^10
%e A092846 a(11)=1001^11
%o A092846 (Sage) def A092846(n) : return (10^binomial(n, n//2).ndigits()+1)^n # _Eric M. Schmidt_, Apr 04 2014
%Y A092846 Cf. A007318, A001020.
%K A092846 nonn,base
%O A092846 0,2
%A A092846 _Jorge Coveiro_, Apr 15 2004