A093909 Let f(k, n) be the product of n consecutive numbers beginning with k. Then a(n) = f(A093908(n))/f(1+n*(n-1)/2).
2, 2, 6, 533, 1272, 1184964, 2728058, 260460615543, 320989537045, 1535738687883866008870, 1660017145844820190523887765476, 1840693015476119977, 8050776919178289031383553134261340
Offset: 1
Keywords
Examples
a(4) = 533= (39*40*41*42)/(7*8*9*10).
Crossrefs
Cf. A093908.
Extensions
More terms from David Wasserman, Apr 25 2007