A097971 Number of alternating runs in all permutations of [n] (the permutation 732569148 has four alternating runs: 732, 2569, 91 and 148).
2, 10, 56, 360, 2640, 21840, 201600, 2056320, 22982400, 279417600, 3672345600, 51891840000, 784604620800, 12640852224000, 216202162176000, 3912561709056000, 74694359900160000, 1500289571708928000, 31627726106296320000, 698242876346695680000
Offset: 2
Keywords
Examples
a(3) = 10 because the permutations 123, 132, 312, 213, 231, 321 have the following alternating runs: 123, 13, 32, 31, 12, 21, 13, 23, 31 and 321.
References
- M. Bona, Combinatorics of Permutations, Chapman & Hall/CRC, Boca Raton, FL, 2004, pp. 24-30.
- D. E. Knuth, The Art of Computer Programming. Addison-Wesley, Reading, MA, 1973, Vol. 3, pp. 46 and 587-8.
Crossrefs
Cf. A006157.
Programs
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Maple
seq(n!*(2*n-1)/3, n=2..20);
Formula
a(n) = n!(2n-1)/3. E.g.f.: x^2*(3-x)/[3(1-x)^2]. a(n) = 2*A006157(n).
Comments