cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A099851 Numbers k such that A099850(k) is divisible by k.

Original entry on oeis.org

1, 3, 16, 57, 112, 160, 272, 404, 20924, 147153, 274617, 4409708, 24881389, 34850872, 39808233, 186610952, 980830465, 1777956414
Offset: 1

Views

Author

Mark Hudson (mrmarkhudson(AT)hotmail.com), Oct 27 2004

Keywords

Examples

			A099850(1)=0, which is divisible by 1.
A099850(3)=3, which is divisible by 3.
A099850(16)=48, which is divisible by 16.
		

Crossrefs

Extensions

a(12)-a(18) from Donovan Johnson, Dec 14 2009

A099852 Terms in A099850 that are divisible by their position in that sequence.

Original entry on oeis.org

0, 3, 48, 798, 2576, 7040, 16864, 48884, 94639252, 4617219681, 20716557246, 5553546567828, 183276908527336, 272413165321136, 335452673952828, 8235555774684392, 224177101582314365, 709201017174989274
Offset: 1

Views

Author

Mark Hudson (mrmarkhudson(AT)hotmail.com), Oct 27 2004

Keywords

Examples

			The 16th term of A099850 is 48, which is divisible by 16. This is the third such term in A099850 that is divisible by its position, so the third term of this sequence is 16.
		

Crossrefs

Formula

a(n)=A099850(A099851(n))

Extensions

a(12)-a(18) from Donovan Johnson, Dec 14 2009

A099853 Values of A099852 divided by the corresponding values in A099851. These are the integer results of dividing the terms of A099850 by their position in that sequence.

Original entry on oeis.org

0, 1, 3, 14, 23, 44, 62, 121, 4523, 31377, 75438, 1259391, 7366024, 7816538, 8426716, 44132221, 228558461, 398885491
Offset: 1

Views

Author

Mark Hudson (mrmarkhudson(AT)hotmail.com), Oct 27 2004

Keywords

Examples

			E.g. A099852 begins 0, 3, 48, 798, 2576,.... and A099851 begins 1, 3, 16, 57, 112,... so the terms of this sequence are 0/1, 3/3, 48/16, 798/57, 2576/112,... which gives 0, 1, 3, 14, 23,...
		

Crossrefs

Formula

a(n)=A099852(n)/A099851(n)

Extensions

a(12)-a(18) from Donovan Johnson, Dec 14 2009
Showing 1-3 of 3 results.