cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A100283 a(n) = floor(p*(n+1)) - floor(p*(n)) - 1 where p = Padovan plastic number = 1.324718... (cf. A060006).

Original entry on oeis.org

0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, 1
Offset: 0

Views

Author

John Lien, Dec 28 2004

Keywords

Comments

A rabbit-like sequence generated by the Padovan plastic number.
The well-known rabbit sequence is generated by taking the difference between the nearest integer less than phi*(n+1) minus the nearest integer less than phi*(n). If this value is 2, then the n-th rabbit sequence value is one. If this value is 1, the n-th rabbit sequence is 0. The sequence given is calculated in a similar manner, but using the plastic constant = 1.324717957244... instead of phi = 1.618033... = (1+sqrt(5))/2. It is 0001 followed by 11 copies of 001 followed by 0001 followed by 12 copies of 001 followed by 11 copies of 001 followed by similar patterns of 0001 followed by n copies of 001 where n is 11 or 12.

References

  • Midhat J. Gazale, Gnomon: From Pharaohs to Fractals, Princeton University Press, 1999

Crossrefs

Programs

  • PARI
    p=(sqrt(23/108)+.5)^(1/3) + (abs( sqrt(23/108) -.5))^(1/3); for(n = 0, n = 200, r = floor(p*(n+1)) - floor(p*n) -1; print (r ))

Extensions

Partially edited by N. J. A. Sloane, Jun 13 2007