A100465 Let p(1)=2, p(2)=3, p(3)=5, ... denote the primes and let E(n) = 1 + p(1) * p(2) * ... * p(n). Sequence gives primes p such that p(n+2) | E(n).
7, 271, 307, 673
Offset: 1
Examples
7 is a term of the sequence, because it is the 4th prime and divides E(2)=2*3+1=7 trivially. - _Martin Ehrenstein_, Feb 05 2021
Extensions
a(2) corrected by Martin Ehrenstein, Feb 05 2021
Comments