cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-1 of 1 results.

A102004 Triangle read by rows: T(n,k) is the number of ordered trees with n edges and having k branches of even length (n>=0, 0<=k<=floor(n/2)).

Original entry on oeis.org

1, 1, 1, 1, 3, 2, 6, 7, 1, 16, 20, 6, 40, 64, 26, 2, 109, 196, 108, 16, 297, 619, 414, 96, 4, 836, 1940, 1557, 484, 45, 2377, 6142, 5690, 2247, 331, 9, 6869, 19454, 20535, 9792, 2010, 126, 20042, 61893, 73123, 40997, 10820, 1116, 21, 59071, 197280, 258220
Offset: 0

Views

Author

Emeric Deutsch, Dec 25 2004

Keywords

Comments

Row n has 1+floor(n/2) terms.
Row sums are the Catalan numbers (A000108).
T(2n,n) = A001006(n-1) for n>=1 (the Motzkin numbers).
T(2n+1,n) = A005717(n+1) for n>=0.

Examples

			T(3,0)=3 because we have: (i) tree with 3 edges hanging from the root, (ii) tree with one edge hanging from the root, at the end of which 2 edges are hanging and (iii) tree with a path of length 3 hanging from the root.
Triangle starts:
1;
1;
1,   1;
3,   2;
6,   7, 1;
16, 20, 6;
		

Crossrefs

Programs

  • Maple
    G:=1/2/(t*z^2+z)*(-z^2+z+1+t*z^2-sqrt(-5*z^2-6*t*z^3-2*z+2*z^3-3*t^2*z^4-2*t*z^2+2*t*z^4+1+z^4)): Gserz:=simplify(series(G,z=0,16)): P[0]:=1: for n from 1 to 14 do P[n]:=sort(expand(coeff(Gserz,z^n))) od:for n from 0 to 14 do seq(coeff(t*P[n], t^k),k=1..1+floor(n/2)) od;

Formula

G.f. G = G(t,z) satisfies z(1+tz)G^2-(1+z-z^2+tz^2)G+1+z-z^2+tz^2=0.
Showing 1-1 of 1 results.