A102827 "True already", base 10, start 1: a(n) is the least integer such that the sequence up to a(n-1) written in base 10 contains floor(a(n)/10) copies of the digit a(n) % 10, with a(0) = 1.
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 22, 23, 24, 25, 26, 27, 28, 29, 33, 34, 35, 36, 37, 38, 39, 44, 45, 46, 47, 48, 49, 55, 56, 57, 58, 59, 66, 67, 68, 69, 77, 78, 79, 88, 89, 99, 111, 112, 113, 114, 115, 116, 117, 118, 119, 122, 123, 124, 125, 126, 127, 128, 129, 133
Offset: 0
Examples
The first 9 values of the sequence written in decimal include no '0's and 1 '1', so the next value cannot be 10 (the count of '0's is not 1) but can be 11.
References
- Inspired by discussion of "True so far" from Eric Angelini (A102357).
Programs
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Maple
A102827aux := proc(n,dig) local c,d ; c := 0 ; for d in convert(n,base,10) do if d = dig then c := c+1 ; end if; end do: c ; end proc: A102827 := proc(n) option remember; local a,a10,ad,cum; if n < 8 then return n+1 ; end if; for a from 1 do a10 := floor(a/10) ; ad := a mod 10 ; cum := add( A102827aux(procname(i),ad),i=0..n-1) ; if cum = a10 then return a; end if; end do: end proc: # R. J. Mathar, Mar 30 2014
Comments