cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A104053 Triangle of coefficients in the numerators of rational functions in tanh(1) that express the (2n)th du Bois-Reymond constants as C_0 = 0, C_2 = -4 - 1/(1-tanh(1)), for n>1, C_2n = -3 - (Sum_{k=0..n} a(n,k)*tanh(1)^k) / (2^n*n! * (1-tanh(1))^n).

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%I A104053 #23 Feb 16 2025 08:32:56
%S A104053 0,1,0,1,-1,-1,-1,0,0,3,1,-5,18,-13,-7,-11,70,-135,65,-10,45,111,-609,
%T A104053 1215,-1350,1275,-621,-141,-1009,6188,-16758,27335,-26845,12474,-2548,
%U A104053 1883,10977,-81353,270004,-511791,584710,-420287,216468,-70169,-3599,-146691,1248210,-4715217,10303461,-14439411
%N A104053 Triangle of coefficients in the numerators of rational functions in tanh(1) that express the (2n)th du Bois-Reymond constants as C_0 = 0, C_2 = -4 - 1/(1-tanh(1)), for n>1, C_2n = -3 - (Sum_{k=0..n} a(n,k)*tanh(1)^k) / (2^n*n! * (1-tanh(1))^n).
%C A104053 For n>0 the row sums = (-1)^(n-1) * (n-1)! For n odd, the sum of the absolute values of the coefficients in the n-th row = (2*(n-1))!/n! (every other entry of A001761).
%C A104053 The sum of the (2n)th du Bois-Reymond constants = 1/5 or is very close to 1/5.
%C A104053 For the 6th and 9th rows, the coefficients were adjusted from results of the residue evaluations so that double factorials ((2n)!! = 2^n*n! (A000165)) are in the denominators. For the 6th row they were multiplied by 3, for the 9th row they were multiplied by 9.
%C A104053 For n>1, Sum_{k=0..n} (n-k+1)*a(n,k) = (-1)^(n)*A001286(n-1) [A001286 are Lah numbers: (n-1)*n!/2].
%H A104053 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/DoubleFactorial.html">Double Factorial</a>.
%H A104053 Eric Weisstein's World of Mathematics, <a href="https://mathworld.wolfram.com/duBois-ReymondConstants.html">du Bois-Reymond Constants</a>.
%F A104053 For n>1, C_2n = -3 - 2 * Residue_{x=i} (x^2/((1+x^2)^n * (tan(x) - x))) (see MathWorld article).
%F A104053 For n>1, Sum_{k=0..n} (-1)^(n+k)*a(n, k) = (2*(n-1))!/n! (i.e., A001761(n-1)).
%t A104053 Table[2 Residue[x^2/((1+x^2)^n (Tan[x]-x)), {x, I}], {n, 0, 9}]
%Y A104053 Cf. A000142, A000165, A001761, A062545, A062546, A085466, A085467.
%K A104053 hard,sign,tabl
%O A104053 0,10
%A A104053 _Gerald McGarvey_, Mar 02 2005
%E A104053 Added the keyword tabl _Gerald McGarvey_, Aug 20 2009