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A104232 Triangle read by rows, based on the morphism f: 1->2, 2->3, 3->{2,1}. First row is 1. If current row is a,b,c,..., then the next row is a,b,c,...,f(a),f(b),f(c),...

%I A104232 #5 Mar 12 2014 16:36:46
%S A104232 1,1,2,1,2,2,3,1,2,2,3,2,3,3,2,1,1,2,2,3,2,3,3,2,1,2,3,3,2,1,3,2,1,2,
%T A104232 1,3,2,1,2,2,3,2,3,3,2,1,2,3,3,2,1,3,2,1,2,1,3,2,2,3,3,2,1,3,2,1,2,1,
%U A104232 3,2,3,2,1,2,1,3,2,2,1,3,2,3,2,2,1,3,1,2,2,3,2,3,3,2,1,2,3,3,2,1,3,2,1,2,1
%N A104232 Triangle read by rows, based on the morphism f: 1->2, 2->3, 3->{2,1}. First row is 1. If current row is a,b,c,..., then the next row is a,b,c,...,f(a),f(b),f(c),...
%C A104232 This substitution was suggested by looking at the Kenyon border tiling substitutions.
%H A104232 Richard Kenyon, <a href="http://arXiv.org/abs/math.MG/9505210">The Construction of Self-Similar Tilings</a>
%t A104232 s[n_] := n /. {1 -> 2, 2 -> 3, 3 -> {2, 1}}; t[a_] := Join[a, Flatten[s /@ a]]; Flatten[ NestList[t, {1}, 6]]
%Y A104232 Cf. A073058.
%K A104232 nonn,tabf
%O A104232 0,3
%A A104232 _Roger L. Bagula_, Apr 02 2005