A104613 Write the natural numbers in base 9 in a triangle with k digits in the k-th row, as shown below. Sequence gives the leading diagonal.
1, 3, 6, 0, 1, 1, 0, 4, 3, 3, 1, 7, 5, 6, 1, 0, 1, 1, 1, 1, 1, 3, 1, 1, 6, 1, 1, 0, 2, 2, 3, 2, 2, 7, 2, 3, 2, 3, 3, 6, 3, 4, 2, 4, 4, 7, 5, 5, 3, 5, 5, 0, 6, 6, 6, 6, 7, 3, 7, 7, 1, 8, 8, 8, 1, 3, 0, 0, 8, 1, 6, 6, 1, 0, 2, 2, 7, 1, 4, 6, 1, 0, 4, 4, 7, 1, 0, 4, 1, 1, 6, 6, 0, 1, 3, 0, 1, 4, 8, 0, 3, 2, 4, 3, 2
Offset: 1
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Programs
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Mathematica
t = Flatten[ IntegerDigits[ Range[1800], 9]]; t[[Table[n(n + 1)/2, {n, 105}]]]
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PARI
{ pln=0; Trn = 1; Trd=1; for(ixp=1, 1625, casi = ixp; cvst=0; while(casi != 0, cvd = casi%9; cvst=10*cvst + cvd + 1; casi = (casi - cvd) / 9 ); while(cvst !=0, ptch = cvst%10; pln++; if(Trn==pln, print1(ptch-1, ", "); Trd++; Trn=Trn+Trd); cvst = (cvst - ptch) / 10 ) ) } \\\ Douglas Latimer, Apr 23 2012
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