A105079 Number of distinct prime divisors of 1000^n - 3 where n = 1,2,3,....
1, 2, 3, 2, 4, 4, 2, 2, 4, 3, 3, 4, 5, 5, 5, 5, 5, 2, 2, 4, 3, 3, 6, 3, 6, 4, 3, 5, 6, 6, 5, 8, 5, 6, 3, 6, 4, 6, 2, 3, 5, 8, 3, 3, 2, 4, 5, 4, 5, 3, 6, 6, 5, 7, 4, 7, 4, 4, 2, 8
Offset: 1
Keywords
Examples
If n=1, then 1000^n - 3 = 1000^1 - 3 = 997 which is a prime, so the first term is 1.