A109849 a(1) = 1, a(2) = 2; a(n) = lcm(n, a(n-2)), a(n+1) = lcm((n+1), a(n-3)) and so on until a(2n-1) = lcm(2n-1, a(1)). Then a(2n) = lcm(2n, a(2n-2)) and so on.
1, 2, 3, 4, 5, 12, 21, 8, 9, 40, 231, 12, 65, 28, 15, 16, 17, 144, 285, 140, 1365, 132, 5313, 120, 225, 104, 189, 84, 145, 60, 93, 32, 33, 544, 3255, 180, 5365, 1596, 2457, 520, 9225, 840, 228459, 132, 4095, 3220, 13395, 144, 833, 400, 255, 364, 3445, 108, 1155
Offset: 1
Keywords
Links
- Ivan Neretin, Table of n, a(n) for n = 1..8193
Crossrefs
Cf. A109850.
Formula
For n > 2, a(n) = lcm(n, a(A080079(n-2))). - Ivan Neretin, Apr 30 2016
Extensions
More terms from Joshua Zucker, May 04 2006
Comments