cp's OEIS Frontend

A113108 Triangle T, read by rows, equal to the matrix square of triangle A113106, which satisfies the recurrence: A113106(n,k) = [A113106^5](n-1,k-1) + [A113106^5](n-1,k).

%I A113108 #3 Mar 30 2012 18:36:51
%S A113108 1,2,1,16,12,1,440,416,62,1,43600,48320,10016,312,1,16698560,20765520,
%T A113108 5394320,246016,1562,1,26098464448,35382716032,10854556720,646408320,
%U A113108 6116016,7812,1,172513149018752,250136469031744,87213434633152
%N A113108 Triangle T, read by rows, equal to the matrix square of triangle A113106, which satisfies the recurrence: A113106(n,k) = [A113106^5](n-1,k-1) + [A113106^5](n-1,k).
%e A113108 Triangle begins:
%e A113108 1;
%e A113108 2,1;
%e A113108 16,12,1;
%e A113108 440,416,62,1;
%e A113108 43600,48320,10016,312,1;
%e A113108 16698560,20765520,5394320,246016,1562,1;
%e A113108 26098464448,35382716032,10854556720,646408320,6116016,7812,1; ...
%o A113108 (PARI) {T(n,k)=local(M=matrix(n+1,n+1));for(r=1,n+1, for(c=1,r, M[r,c]=if(r==c,1,if(c>1,(M^5)[r-1,c-1])+(M^5)[r-1,c]))); return((M^2)[n+1,k+1])}
%Y A113108 Cf. A113106.
%K A113108 nonn,tabl
%O A113108 0,2
%A A113108 _Paul D. Hanna_, Oct 14 2005