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A114892 a(n) is the cycle length corresponding to A114891(n).

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%I A114892 #2 Mar 30 2012 17:27:48
%S A114892 2,2,3,4,2,4,2,4,2,4,2,6,4,2,4,2,4,2,4,2,6,4,2,4,2,4,2,4,2,6,4,2,4,2,
%T A114892 4,2,4,2,6,4,2,4,2,4,2,4,2,6,4,2,4,2,4,2,4,2,6,4,2,4,2,4,2,4,2,10,2,4,
%U A114892 2,4,2,4,2,6,4,2,4,2,4,2,4,2,6,4,2,4,2,4,2,4,2,6,4,2,4,2,4,2,4,2,6,4,2,4,2
%N A114892 a(n) is the cycle length corresponding to A114891(n).
%C A114892 Besides 3 for the cycle (5,7,6) the following lengths of cycles with elements <= 1500000 occur: 2, 4, 6, 10, 12, 16, 18. The even period lengths appear in a rather regular manner, presumably infinitely often.
%e A114892 A114727(12) = 32 belongs to the 6-cycle (32,37,36,35,34,33), so a(12) = 6.
%Y A114892 Cf. A114861, A114891.
%K A114892 nonn
%O A114892 1,1
%A A114892 _Klaus Brockhaus_, Jan 09 2006