A115778 -id:A115778 - cp's OEIS frontend

A115777 Levenshtein distance between n considered as a decimal string and n considered as a binary string.

0, 2, 2, 3, 3, 3, 3, 4, 4, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 4, 4, 6, 6, 6, 6, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 5, 5, 6, 6, 7, 7, 7, 7, 7, 7, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 4, 4, 5, 5, 5, 5

Offset: 1

Robert G. Wilson v, Jan 26 2006

a(n) = minimal number of editing steps (delete, insert or substitute) to transform n_10 into n_2.

Michael Gilleland, Levenshtein Distance [It has been suggested that this algorithm gives incorrect results sometimes. - _N. J. A. Sloane_]

Cf. A000027, A007088, first occurrence: A115778.

levenshtein[s_List, t_List] := Module[{d, n = Length@s, m = Length@t}, Which[s === t, 0, n == 0, m, m == 0, n, s != t, d = Table[0, {m + 1}, {n + 1}]; d[[1, Range[n + 1]]] = Range[0, n]; d[[Range[m + 1], 1]] = Range[0, m]; Do[d[[j + 1, i + 1]] = Min[d[[j, i + 1]] + 1, d[[j + 1, i]] + 1, d[[j, i]] + If[s[[i]] === t[[j]], 0, 1]], {j, m}, {i, n}]; d[[ -1, -1]]]];
f[n_] := levenshtein[ IntegerDigits[n], IntegerDigits[n, 2]]; Array[f, 105]

A115779 Consider the Levenshtein distance between k considered as a decimal string and k considered as a binary string. Then a(n) is the greatest number m such that the Levenshtein distance is n or 0 if no such number exists.

Original entry on oeis.org

1, 0, 11, 15, 111, 121, 1011, 1111, 2011, 11111, 16111, 111111, 131011, 1011111, 1111111, 2011111, 11111111, 16111111, 111111111, 131111111, 1011111111, 1111111111, 2111111111, 11111111111

Offset: 0

Robert G. Wilson v, Jan 26 2006

Difference between A115779&A115778: 1, 0, 9, 11, 103, 99, 979, 1047, 1789, 10855, 15599, 109067, 128789, 1006889, 1102919, 1988889, 11078343, ...,.

Cf. A000027, A007088, A115777.

levenshtein[s_List, t_List] := Module[{d, n = Length@s, m = Length@t}, Which[s === t, 0, n == 0, m, m == 0, n, s != t, d = Table[0, {m + 1}, {n + 1}]; d[[1, Range[n + 1]]] = Range[0, n]; d[[Range[m + 1], 1]] = Range[0, m]; Do[d[[j + 1, i + 1]] = Min[d[[j, i + 1]] + 1, d[[j + 1, i]] + 1, d[[j, i]] + If[s[[i]] === t[[j]], 0, 1]], {j, m}, {i, n}]; d[[ -1, -1]]]];
t = Table[0, {25}]; f[n_] := levenshtein[ IntegerDigits[n], IntegerDigits[n, 2]]; Do[ t[[f@n+1]] = n, {n, 10^6}]; t

a(1)=0 since no number satisfies the definition and generally a(n)>= 2^(n+1).

a(18)-a(23) from Lars Blomberg, Jul 16 2015

cp's OEIS Frontend

A115777 Levenshtein distance between n considered as a decimal string and n considered as a binary string.

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