A245783 Numbers n such that the hexagonal number H(n) is equal to the sum of the pentagonal numbers P(m) and P(m+1) for some m.
1, 2, 57, 166, 5561, 16242, 544897, 1591526, 53394321, 155953282, 5232098537, 15281830086, 512692262281, 1497463395122, 50238609604977, 146736130891846, 4922871049025441, 14378643364005762, 482391124194888217, 1408960313541672806, 47269407300050019801
Offset: 1
Examples
57 is in the sequence because H(57) = 6441 = 3151+3290 = P(46)+P(47).
Links
- Colin Barker, Table of n, a(n) for n = 1..1000
- Index entries for linear recurrences with constant coefficients, signature (1,98,-98,-1,1).
Programs
-
PARI
Vec(-x*(6*x^4+11*x^3-43*x^2+x+1)/((x-1)*(x^2-10*x+1)*(x^2+10*x+1)) + O(x^100))
Formula
a(n) = a(n-1)+98*a(n-2)-98*a(n-3)-a(n-4)+a(n-5).
G.f.: -x*(6*x^4+11*x^3-43*x^2+x+1) / ((x-1)*(x^2-10*x+1)*(x^2+10*x+1)).
Comments