A127741 a(n) = (n+1) * A005493(n).
1, 6, 30, 148, 755, 4044, 22841, 136056, 853452, 5625950, 38885297, 281170080, 2122313505, 16688829122, 136457754030, 1158155642512, 10186602918035, 92711977180164, 871936904575985, 8462913158427580, 84668764368102012, 872196382566014506, 9241557859113581689
Offset: 0
Keywords
Examples
a(n) = sum of terms in n-th row of A127740. a(2) = 30 = (6 + 9 + 15).
Links
- Chai Wah Wu, Table of n, a(n) for n = 0..250
Programs
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Mathematica
lim=24;A005493=Differences[BellB[Range[lim]]];Array[(#+1)*A005493[[#+1]]&,lim-1,0] (* James C. McMahon, Jan 02 2025 *)
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Python
# requires Python 3.2 or higher. Otherwise use def'n of accumulate in Python docs. from itertools import accumulate A127741_list, blist, b = [], [1], 1 for n in range(1,1001): blist = list(accumulate([b]+blist)) b = blist[-1] A127741_list.append(blist[-2]*n) # Chai Wah Wu, Sep 20 2014
Formula
a(n) = (n+1) * A005493(n).
Extensions
Edited by Jon E. Schoenfield, May 27 2019