cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A128728 Triangle read by rows: T(n,k) is the number of skew Dyck paths of semilength n and having k UDL's (n >= 0; 0 <= k <= floor((n+1)/2)).

Original entry on oeis.org

1, 1, 2, 1, 6, 4, 20, 16, 71, 64, 2, 262, 261, 20, 994, 1084, 141, 3852, 4572, 854, 7, 15183, 19520, 4772, 112, 60686, 84139, 25416, 1128, 245412, 365404, 131270, 9120, 30, 1002344, 1596420, 664004, 64790, 660, 4129012, 7008544, 3309336, 422928
Offset: 0

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Author

Emeric Deutsch, Mar 31 2007

Keywords

Comments

A skew Dyck path is a path in the first quadrant which begins at the origin, ends on the x-axis, consists of steps U=(1,1)(up), D=(1,-1)(down) and L=(-1,-1)(left) so that up and left steps do not overlap. The length of a path is defined to be the number of steps in it.
Row n has 1 + floor((n+1)/3) terms.
Row sums yield A002212.
T(n,0) = A128729(n).
Sum_{k>=0} k*T(n,k) = A128730(n).
Apparently, T(3k-1,k) = binomial(3k-1,k)/(3k-1) = A006013(k-1).

Examples

			T(3,1)=4 because we have UDUUDL, UUUDLD, UUDUDL and UUUDLL.
Triangle starts:
    1;
    1;
    2,   1;
    6,   4;
   20,  16;
   71,  64,   2;
  262, 261,  20;
		

Crossrefs

Programs

  • Maple
    eq:=z^2*G^3-z*(2-z)*G^2+(1-z^2)*G-1+z+z^2-t*z^2=0: G:=RootOf(eq,G): Gser:=simplify(series(G,z=0,17)): for n from 0 to 14 do P[n]:=sort(coeff(Gser,z,n)) od: for n from 0 to 14 do seq(coeff(P[n],t,j),j=0..floor((n+1)/3)) od; # yields sequence in triangular form

Formula

G.f.: G = G(t,z) satisfies z^2*G^3 - z(2-z)G^2 + (1-z^2)G - 1 + z + z^2 - tz^2 = 0.

A303952 a(n) is the number of monic polynomials P(z) of degree n over the complex numbers such that P(z) divides P(z^2).

Original entry on oeis.org

1, 2, 5, 17, 69, 302, 1367, 6302, 29401, 138356, 655425, 3121439, 14930541, 71675840, 345148893, 1666432817, 8064278289, 39103576700, 189949958333, 924163714217, 4502711570989, 21966152501240, 107284324830303
Offset: 0

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Author

Jianing Song, May 03 2018

Keywords

Comments

Note that if z_0 is a root of P(z), so is (z_0)^2, so |z_0| must equal to 0 or 1. As a result, all such polynomials must have the form P(z) = z^d_0 * Product_{j=1..k} (z - exp(2*Pi*i*q_j))^d_j, where Sum_{j=0..k} d_j = n and {q_1, q_2, ..., q_k} is a set of k rational numbers on [0,1) such that if x belongs to it, the fractional part of 2x also belongs to it. That explains the formula a(n) = Sum_{k=1..n} binomial(n,k)*A014300(k) + 1 in the formula section, the "+1" represents the case d_0 = n and k = 0 corresponding to the polynomial P(z) = z^n.

Examples

			For n = 0, P(z) = 1.
For n = 1, P(z) = z or z - 1.
For n = 2, P(z) = z^2, z^2 - 1, z^2 - 2z + 1, z^2 + z or z^2 + z + 1.
		

Crossrefs

Programs

  • PARI
    x='x+O('x^50); Vec(2*x/(1-6*x+5*x^2+(1+x)*sqrt(1-6*x+5*x^2))+1/(1-x))

Formula

a(n) = Sum_{k=1..n} binomial(n,k)*A014300(k) + 1. The "+1" represents the polynomial P(z) = z^n.
a(n) = A128730(n+1) + 1.
G.f.: 2x/(1-6x+5x^2+(1+x)sqrt(1-6x+5x^2)) + 1/(1-x).
D-finite with recurrence: +2*n*a(n) +(-13*n+4)*a(n-1) +2*(7*n+3)*a(n-2) +8*(n-7)*a(n-3) +2*(-8*n+33)*a(n-4) +5*(n-4)*a(n-5)=0. - R. J. Mathar, Jan 27 2020
D-finite with recurrence 2*n*a(n) +(-11*n+2)*a(n-1) +(3*n+19)*a(n-2) +(11*n-40)*a(n-3) +5*(-n+3)*a(n-4) +4=0. - R. J. Mathar, Aug 01 2022
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