cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A129718 Triangle read by rows: T(n,k) is the number of Fibonacci binary words of length n and having k runs of 1's (n >= 0, 0 <= k <= floor((n+1)/2)). A Fibonacci binary word is a binary word having no 00 subword. A run of 1's is a maximal subword of the form 11..1.

Original entry on oeis.org

1, 1, 1, 0, 3, 0, 4, 1, 0, 4, 4, 0, 4, 8, 1, 0, 4, 12, 5, 0, 4, 16, 13, 1, 0, 4, 20, 25, 6, 0, 4, 24, 41, 19, 1, 0, 4, 28, 61, 44, 7, 0, 4, 32, 85, 85, 26, 1, 0, 4, 36, 113, 146, 70, 8, 0, 4, 40, 145, 231, 155, 34, 1, 0, 4, 44, 181, 344, 301, 104, 9, 0, 4, 48, 221, 489, 532, 259, 43, 1
Offset: 0

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Author

Emeric Deutsch, May 12 2007

Keywords

Comments

Row n has 1+floor((n+1)/2) terms.
Row sums are the Fibonacci numbers (A000045).
T(n,k) = A129717(n,k-1) (since in each word the number of runs of 1's = 1 + the number of 101's).
Sum_{k=0..floor((n+1)/2)} k*T(n,k) = A055244(n) (n >= 1).

Examples

			T(6,3)=5 because we have 110101, 101101, 101010, 101011 and 010101.
Triangle starts:
  1;
  1,  1;
  0,  3;
  0,  4,  1;
  0,  4,  4;
  0,  4,  8,  1;
  0,  4, 12,  5;
		

Crossrefs

Programs

  • Maple
    G:=(1+z)*(1-z+t*z)/(1-z-t*z^2): Gser:=simplify(series(G,z=0,21)): for n from 0 to 18 do P[n]:=sort(coeff(Gser,z,n)) od: for n from 0 to 17 do seq(coeff(P[n],t,j),j=0..ceil(n/2)) od; # yields sequence in triangular form

Formula

G.f. = G(t,z) = (1+z)(1-z+tz)/(1-z-tz^2).
T(n,k) = binomial(n-k,k-1) + 2*binomial(n-k-1,k-1) + binomial(n-k-2,k-1) for n >= 4 and 0 <= k < floor((n+1)/2).
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