This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.
%I A130190 #37 Aug 06 2021 05:07:14 %S A130190 1,2,6,4,15,12,42,24,90,10,33,8,910,105,90,48,255,180,3990,420,6930, %T A130190 330,345,720,13650,273,378,28,145,20,14322,2464,117810,3570,7,24, %U A130190 1919190,1729,2730,840,9471,13860,99330,1540,217350,4830,4935,10080,324870 %N A130190 Denominators of z-sequence for the Sheffer matrix (triangle) A094816 (coefficients of Poisson-Charlier polynomials). %C A130190 The numerators are given in A130189. %C A130190 See A130189 for the W. Lang link on z-sequences for Sheffer matrices. %C A130190 The prime factors of each a(n) are such that n!/a(n) has the prime, p = n+1, as the denominator of its reduced fraction, and if n+1 is not prime then n!/a(n) is an integer, except at n = 3, which has denominator = 2. Also see alternate formula for a(n) below. - _Richard R. Forberg_, Dec 28 2014 %C A130190 As implied above, at n = p-1 the largest prime factor of a(n) is p. For a(m), where m is an integer within the set given by A089965, the two largest prime factors of a(m) are m+1 and (m+1)/2. Furthermore, it appears, when n+1 is not a prime no prime factor of a(n) is greater than k/2, where k is the next higher value of n where n+1 is prime. Two examples at this upper limit of k/2 are n = 104 and 105, where the highest prime factor of a(n) is 53; it is then at n = k = 106 where n+1 is prime. - _Richard R. Forberg_, Jan 01 2015 %H A130190 G. C. Greubel, <a href="/A130190/b130190.txt">Table of n, a(n) for n = 0..1000</a> %F A130190 a(n) = denominator(z(n)),n>=0, with the e.g.f. for z(n) given in A130189. %F A130190 Denominator of Sum_{k=0..n} A048993(n,k)/(k+1). - _Peter Luschny_, Apr 28 2009 %F A130190 Alternate: a(n) = denominator((1/e)*Sum_{k>=0}*(Sum_{j=0..k} j^n/k!)). NOTE: Numerators are different from A130189, and given by A248716. - _Richard R. Forberg_, Dec 28 2014 %F A130190 This more generalized expression ((1/e)*Sum_{k>=0} (Sum_{j=0..k} (j+m)^n/k!)), gives the same denominators for any integer m. - _Richard R. Forberg_, Jan 14 2015 %p A130190 seq(denom(add(Stirling2(n,k)/(k+1),k=0..n)),n=0..20); # _Peter Luschny_, Apr 28 2009 %t A130190 Denominator[Table[(1/Exp[1])* Sum[Sum[j^n/k!, {j, 0, k}], {k, 0, Infinity}], {n, 0, 100}]] (* _Richard R. Forberg_, Dec 28 2014 *) %t A130190 Table[Denominator[Sum[StirlingS2[n, k]/(k + 1), {k, 0, n}]], {n, 0, 50}] (* _G. C. Greubel_, Jul 10 2018 *) %o A130190 (PARI) a(n) = denominator(sum(k=0, n, stirling(n, k, 2)/(k+1))); \\ _Michel Marcus_, Jan 15 2015, after Maple %Y A130190 Cf. A089965, A094816, A248716, A130189. %K A130190 nonn,easy %O A130190 0,2 %A A130190 _Wolfdieter Lang_, Jun 01 2007