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A133910 Period numbers of A133900 divided by n^2.

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%I A133910 #2 Mar 31 2012 13:21:04
%S A133910 1,1,1,1,1,2,1,1,1,4,1,6,1,4,3,1,1,8,1,4,3,8,1,6,1,8,1,4,1,360,1,1,9,
%T A133910 16,5,24,1,16,9,20,1,144,1,8,15,16,1,18,1,16,9,8,1,16,5,28,9,16,1,360,
%U A133910 1,16,21,1,5,288,1,16,9,1120,1,24,1,32,9,16,7,288,1,20,1,64,1,6048,5,32,27,8
%N A133910 Period numbers of A133900 divided by n^2.
%F A133910 a(n)=A133900(n)/n^2.
%F A133910 a(n)=1, iff n is a prime or a power of a prime (including n=1).
%F A133910 If a prime p is a factor of a(n), then p is also a factor of n.
%e A133910 a(6)=2, since A133900(6)/6^2=72/36=2.
%e A133910 a(18)=8, since A133900(18)/18^2=2592/324=8.
%Y A133910 Cf. A000040, A100118, A046363, A133620, A133621, A133623, A133630, A133635.
%Y A133910 Cf. A133872, A133880, A133890, A133900, A133911.
%K A133910 nonn
%O A133910 1,6
%A A133910 _Hieronymus Fischer_, Oct 20 2007