This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.
%I A153415 #36 Jan 14 2023 13:24:03
%S A153415 5,6,6,1,7,7,6,7,5,8,1,1,3,8,4,5,5,0,2,7,5,9,2,9,3,2,1,2,1,2,0,6,2,0,
%T A153415 0,3,7,3,6,1,4,4,1,9,7,8,6,5,9,0,5,5,7,0,4,9,2,3,4,4,4,1,3,2,5,4,5,7,
%U A153415 5,5,5,4,5,3,0,2,0,8,6,8,5,6,1,4,8,5,5,6,7,8,4,2,1,8,1,8,3,2,6,6,4,6,1,5,3
%N A153415 Decimal expansion of Sum_{n>=1} 1/A000032(2*n).
%C A153415 From _Peter Bala_, Oct 15 2019: (Start)
%C A153415 c = (1/4)*(theta_3( (3-sqrt(5))/2 )^2 - 1 ), where theta_3(q) = 1 + 2*Sum_{n >= 1} q^n^2. See Borwein and Borwein, Proposition 3.5 (i), p. 91. Cf. A056854.
%C A153415 Series acceleration formulas (L(n) = A000032(n)):
%C A153415 c = 1 - 5*Sum_{n >= 1} 1/( L(2*n)*(L(2*n)^2 - 5) ).
%C A153415 c = (1/6) + 15*Sum_{n >= 1} 1/( L(2*n)*(L(2*n)^2 + 5) ).
%C A153415 c = (11/16) - 10*Sum_{n >= 1} (L(2*n)^2 - 10)/( L(2*n)*(L(2*n)^2 - 5)*(L(2*n)^2 - 20) ). (End)
%C A153415 Compare with Sum_{n >= 1} 1/(L(2*n) - sqrt(5)) = phi and Sum_{n >= 1} 1/(L(2*n) + sqrt(5)) = 2 - phi, where phi = (sqrt(5) + 1)/2. - _Peter Bala_, Nov 23 2019
%C A153415 This constant is transcendental (Duverney et al., 1997). - _Amiram Eldar_, Oct 30 2020
%D A153415 J. M. Borwein and P. B. Borwein, Pi and the AGM, Wiley, 1987, p. 91.
%H A153415 Daniel Duverney, Keiji Nishioka, Kumiko Nishioka and Iekata Shiokawa, <a href="http://doi.org/10.3792/pjaa.73.140">Transcendence of Rogers-Ramanujan continued fraction and reciprocal sums of Fibonacci numbers</a>, Proceedings of the Japan Academy, Series A, Mathematical Sciences, Vol. 73, No. 7 (1997), pp. 140-142.
%H A153415 <a href="/index/Tra#transcendental">Index entries for transcendental numbers</a>
%e A153415 0.56617767581138455027...
%t A153415 First[ RealDigits[ N[(EllipticTheta[3, 0, GoldenRatio^(-2)]^2 - 1)/4, 120], 10, 105]](* _Jean-François Alcover_, Jun 07 2012, after _Eric W. Weisstein_ *)
%o A153415 (PARI) th3(x)=1 + 2*suminf(n=1,x^n^2)
%o A153415 phi=(sqrt(5)+1)/2
%o A153415 (th3(phi^-2)^2-1)/4 \\ _Charles R Greathouse IV_, Jun 06 2016
%Y A153415 Cf. A000032, A000122, A056854, A093540, A153416.
%K A153415 nonn,cons
%O A153415 0,1
%A A153415 _Eric W. Weisstein_, Dec 25 2008