A155892 Least positive integer such that a(n)! starts with n, both written in base 3.
1, 2, 12, 5, 13, 3, 19, 4, 31, 18, 12, 21, 5, 33, 17, 13, 34, 8, 38, 7, 19, 92, 24, 4, 11, 6, 46, 39, 31, 22, 18, 77, 12, 55, 32, 75, 21, 52, 74, 5, 15, 33, 61, 122, 166, 17, 47, 13, 65, 54, 49, 148, 34, 71, 8, 117, 107, 60, 38, 51, 10, 7, 111, 25, 19, 92, 123, 128, 29, 24, 56, 99
Offset: 1
Examples
a(4) = 5 since 4 = 11[3] (i.e. written in base 2) and 5! = 11110[3] is the least factorial to have 11 as most significant digits in base 3.
Programs
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PARI
A155892(n)={ local( F=1,k=1 ); while( F\1!=n, F*=k++; while( F>=n+1, F/=3 )); k}