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A156985 Triangle formed by coefficients of the expansion of p(x,n) = (1-x)^(2*n + 1)*Sum_{j >= 0} (1 +j +j^2)^n * x^j.

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%I A156985 #7 Jan 08 2022 03:42:35
%S A156985 1,1,0,1,1,4,14,4,1,1,20,175,328,175,20,1,1,72,1708,9784,17190,9784,
%T A156985 1708,72,1,1,232,14189,199616,884498,1431728,884498,199616,14189,232,
%U A156985 1,1,716,108250,3353948,31986447,115907544,176287788,115907544,31986447,3353948,108250,716,1
%N A156985 Triangle formed by coefficients of the expansion of p(x,n) = (1-x)^(2*n + 1)*Sum_{j >= 0} (1 +j +j^2)^n * x^j.
%H A156985 G. C. Greubel, <a href="/A156985/b156985.txt">Rows n = 0..50 of the irregular triangle, flattened</a>
%F A156985 T(n, k) = coefficients of the expansion of p(x, n), where p(x,n) = (1-x)^(2*n + 1)*Sum_{j >= 0} (1 +j +j^2)^n * x^j.
%F A156985 Sum_{k=0..2*n} T(n, k) = A010050(n).
%e A156985 Irregular triangle begins as:
%e A156985   1;
%e A156985   1,   0,     1;
%e A156985   1,   4,    14,      4,      1;
%e A156985   1,  20,   175,    328,    175,      20,      1;
%e A156985   1,  72,  1708,   9784,  17190,    9784,   1708,     72,     1;
%e A156985   1, 232, 14189, 199616, 884498, 1431728, 884498, 199616, 14189, 232, 1;
%t A156985 p[x_, n_] = (1-x)^(2*n+1)*Sum[(1+k+k^2)^n*x^k, {k, 0, Infinity}];
%t A156985 Table[CoefficientList[p[x, n], x], {n, 0, 10}]//Flatten
%o A156985 (Sage)
%o A156985 def T(n, k): return ( (1-x)^(2*n+1)*sum((j^2+j+1)^n*x^j for j in (0..2*n+1)) ).series(x, 2*n+2).list()[k]
%o A156985 flatten([1]+[[T(n, k) for k in (0..2*n)] for n in (1..12)]) # _G. C. Greubel_, Jan 07 2022
%Y A156985 Cf. A010050, A156896, A156890, A156901, A156918.
%K A156985 nonn,tabf
%O A156985 0,6
%A A156985 _Roger L. Bagula_, Feb 20 2009
%E A156985 Edited by _G. C. Greubel_, Jan 07 2022