A159580 Integral quotients occur consecutively this many times (in sequence associated with A051838 and A116536).
2, 3, 2, 3, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 2, 2, 3, 2, 2, 2, 3, 2, 2, 3, 3, 2, 3, 2, 4, 4, 2, 2, 2, 2, 2, 2, 3, 2, 2, 3, 2, 2, 3, 3, 2, 2, 2, 2, 2, 3, 3, 2, 3, 2, 2, 3, 2, 3, 3, 2, 2, 2, 3, 2, 2, 3, 2, 2, 2, 5, 2, 2, 2, 2, 2, 2, 2, 4, 2
Offset: 1
Examples
a(1)=2 because the 1st subsequence (38,39) of consecutive integers has run length 2. a(2)=3 because the 2nd subsequence is (56,57,58) which has run length 3. a(3)=2 because the 3rd subsequence is (167,168) which has run length 2.
Extensions
Recomputed based on b-file of A051838. - R. J. Mathar, Aug 28 2018
Comments