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This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A160455 Number of triangles that can be built from rods with lengths 1,2,...,n by using and concatenating all rods.

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%I A160455 #15 Sep 05 2021 19:20:21
%S A160455 0,2,7,12,16,27,48,70,91,127,184,243,300,385,507,631,752,919,1141,
%T A160455 1365,1587,1875,2241,2611,2977,3434,3997,4563,5125,5808,6627,7450,
%U A160455 8269,9241,10384,11532,12675,14008,15552,17101,18644,20419,22447
%N A160455 Number of triangles that can be built from rods with lengths 1,2,...,n by using and concatenating all rods.
%C A160455 a(n) is the number of triples (a,b,c) with b+c > a >= b >=c > 0 such that three disjoint subsets A,B,C of {1,2,...,n} with respective element sums a,b,c exist.
%C A160455 a(n) is also the number of partitions as counted in A160438 with additional constraint that there are only three parts and these satisfy the triangle inequality.
%H A160455 H. v. Eitzen, <a href="/A160455/b160455.txt">Table of n, a(n) for n=3..10000</a>
%H A160455 "AI", <a href="http://groups.google.com/group/sci.math/browse_frm/thread/70c1521d9143d634">(Sci.math thread that inspired investigating the sequence)</a>
%H A160455 H. v. Eitzen, <a href="http://www.von-eitzen.de/math/trianglesticks.pdf">How to Build Triangles from Integers</a>
%F A160455 If n<=2, a(n)=0 trivially because three edges need at least three rods.
%F A160455 If n>=4, then a(n) = A005044(n*(n+1)/2), i.e. for n big enough all triangles of suitable perimeter can be obtained.
%F A160455 Conjectures from _Colin Barker_, May 12 2019: (Start)
%F A160455 G.f.: x^4*(2 - x + 2*x^2 - 3*x^3 + 6*x^4 - 5*x^5 + 8*x^6 - 9*x^7 + 11*x^8 - 11*x^9 + 11*x^10 - 10*x^11 + 10*x^12 - 8*x^13 + 5*x^14 - 3*x^15 + x^16) / ((1 - x)^5*(1 + x^2)^3*(1 + x + x^2)*(1 + x^4)).
%F A160455 a(n) = 4*a(n-1) - 9*a(n-2) + 17*a(n-3) - 27*a(n-4) + 37*a(n-5) - 47*a(n-6) + 55*a(n-7) - 59*a(n-8) + 59*a(n-9) - 55*a(n-10) + 47*a(n-11) - 37*a(n-12) + 27*a(n-13) - 17*a(n-14) + 9*a(n-15) - 4*a(n-16) + a(n-17) for n>20.
%F A160455 (End)
%e A160455 For n=3, only one integer-sided triangle with perimeter 1+2+3=6 exists, namely (2,2,2). This cannot be built from rods of length 1,2 and 3. Therefore a(3)=0.
%e A160455 For n=4, two triangles with perimeter 1+2+3+4=10 exist: (4,4,2) and (4,3,3); both can be built from the available rods: (4,1+3,2) and (4,3,1+2). Therefore a(4)=2.
%Y A160455 A002623 is a similar problem where one rod per edge is to be used.
%K A160455 easy,nonn
%O A160455 3,2
%A A160455 _Hagen von Eitzen_, May 14 2009